The maximum height attained is 460 m.
<h3>What is the maximum height?</h3>
We know that the final velocity of a body is 0 m/s at the maximum height which is the greatest height that is attained by the body. We now use the formula;
v^2 = u^2 -2gh
Given that v = 0 m/s
u^2 = 2gh
h = u^2/2g
v = final velocity
u = initial velocity
h = maximin height
g = acceleration due to gravity
h = (95)^2/2 * 9.8
h = 460 m
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Answer:
E = 1/2 M V^2 = 1/2 P V since P = M V
E2 / E1 = P2 V2 / (P1 V1)
P2 / P1 = E2 V1 / (E1 V2) = V2^2 V1 / (V1^2 V2) = V2 / V1
E2 / E1 = V2^2 / V1^2
V2 / V1 = (E2 / E1)^1/2
V2 / V1 = (.9)1/2 = .95
The linear momentum would have to decrease by 5%
48 M to get the answer add the area of the triangle and rectangle under the line
Answer:
(D) 42.4N
Explanation:
Since the frame is at rest, the net force acting on it must be 0. There are three forces acting on it: the gravity and the opposing forces of the two cables.
Since the gravity is a vertical force, we are only interested in the vertical components of the remaining forces. The net force equation is
F_net = 0 = F_g -2 * F_y
The vertical force of one cable (using the information in the drawing) is:
F_y = 30N * sin 45 deg = 21.21N
Now the weight can be determined:
0 = F_g - 2 * F_y
F_g= 2 * F_y = 2 * 21.21N = 42.4N
The weight of the frame is about 42.4N.
Answer:
Explanation:
Using Newton's second law:
Where 
is the force applied on the object, 
is the mass of the object, and 
is the acceleration.
In this case we need the acceleration, so we clear for :
we know that the force is: 
, and the mass: 
so the acceleration:
the acceleration of the block is:
