The train is accelerated from rest at a speed of 0.11 m/s2 to reach a speed of 15.6 m/s. After reaching that speed the train mov
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Answer:
y = 67.6 feet, y = 114.4/ (22 - 3t)
Explanation:
For this exercise let's use that light travels in a straight line and some trigonometric relationships, the symbols are in the attached diagram
Large triangle Projector up to the screen
tan θ = y / L
For the small triangle. Projector up to the person
tan θ = y₀ / (L-d)
The angle is the same, so we equate the two equations
y₀ / (L -d) = y / L
y = y₀ L / (L-d)
The distance from the screen (d), we look for it with kinematics
v = d / t
d = v t
we replace
y = y₀ L / (L - v t)
y = 5.2 22 / (22 - 3 t)
y = 114.4 (22 - 3t)⁻¹
This is the equation of the shadow height change as a function of time
For the suggested distance the shadow has a height of
y = 114.4 / (22-13)
y = 67.6 feet
Using the Universal Gratitation Law, we have:
Again applying the formula in the new situation, comes:
Number 4
If you notice any mistake in my english, please let me know, because i am not native.
Again applying the formula in the new situation, comes:
Number 4
If you notice any mistake in my english, please let me know, because i am not native.