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inn [45]
3 years ago
14

The table shows the changes in velocity for several different cars. Each change takes place over a 10-second interval. Which car

s are either speeding up or slowing down?
Physics
2 answers:
sesenic [268]3 years ago
6 0
Car B, Car C, And Car E Are either speeding up or slowing down
erica [24]3 years ago
3 0

Answer:

B, C, E are the right answers

Explanation:

I got this question on a test and got these as the right answers

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Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne
VLD [36.1K]

Answer:

The the maximum emf is 2.52\times10^{-11}\ V

Explanation:

Given that,

Magnetic field B = 1.40\times10^{-3}\ T

Frequency = 60 Hz

Diameter = 7.8 μm

We need to calculate the maximum emf

Using formula of emf

\epsilon=NBA\omega

Where, N = number of turns

B= magnetic field

A = area

Put the value in to the formula

\epsilon=1\times1.40\times10^{-3}\times\pi\times(\dfrac{7.8\times10^{-6}}{2})^2\times2\times\pi\times60

\epsilon=2.52\times10^{-11}\ V

Hence, The the maximum emf is 2.52\times10^{-11}\ V

5 0
3 years ago
If the mass of 293nv is 293.15 amu and that of 295nv is 295.30 amu , what is the atomic weight of nv?
expeople1 [14]
Honestly, I am quite confused with what Nv stands for because there is no element with that symbol. However, I still get the concept of finding the average molecular mass of an element. Let's just assume that nv stands for a specific type of element and it has two isotopes: nv-293 and nv-295. Isotopes have the same number of protons but differ in mass number (protons+neutrons). 

To find the average atomic weight, just multiply the individual weights with the respective composition of the isotope. Since there are only two isotopes, they constitute 50% each. So, the average atomic weight is 

(50%)(293.15 amu) + (50%)(<span>295.30 amu) = 294.225 amu

Hence, the atomic weight of nv is 294.225 atomic mass units.</span>
5 0
3 years ago
a star is seen to have two transiting planets. planet 1 transits every 3 months, and planet 2 transits every 15 months. what can
WINSTONCH [101]
Planet 1 orbits 3x as quick as planet 2
4 0
2 years ago
what logging method greatest impact on forest ecosystems
lora16 [44]
Are there options to choose e
3 0
3 years ago
A proton is traveling horizontally to the right at 4.20×10^6m/s.Part A:Find (a)the magnitude and (b) direction of the weakest el
anygoal [31]

Answer:

2630250 N/C, horizontally left

0

1.67\times 10^{-8}\ s

1434.825 N/C, horizontally left

Explanation:

m = Mass of particle

u = Initial velocity = 4.2\times 10^6\ m/s

v = Final velocity = 0

t = Time taken

s = Displacement = 3.5 cm

q = Charge of particle = 1.6\times 10^{-19}\ C

Force is given by

F=qE

Acceleration is given by

a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times E}{1.67\times 10^{-27}}\\\Rightarrow a=95808383.23353E

v^2-u^2=2as\\\Rightarrow v^2-u^2=2\times 95808383.23353Es\\\Rightarrow E=\dfrac{0^2-(4.2\times 10^6)^2}{2\times 95808383.23353\times 0.035}\\\Rightarrow E=-2630250\ N/C

Magnitude of electric field is 2630250 N/C

Direction is horizontally to the left

The angle counterclockwise from left is zero.

a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times -2630250}{1.67\times 10^{-27}}\\\Rightarrow a=-2.52\times 10^{14}\ m/s^2

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-4.2\times 10^6}{-2.52\times 10^{14}}\\\Rightarrow t=1.67\times 10^{-8}\ s

The time taken is 1.67\times 10^{-8}\ s

Acceleration is given by

a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{qE}{m}\\\Rightarrow a=\dfrac{1.6\times 10^{-19}\times E}{9.11\times 10^{-31}}\\\Rightarrow a=175631174533.4797E

v^2-u^2=2as\\\Rightarrow v^2-u^2=2\times 175631174533.4797Es\\\Rightarrow E=\dfrac{0^2-(4.2\times 10^6)^2}{2\times 175631174533.4797\times 0.035}\\\Rightarrow E=-1434.825\ N/C

Magnitude of electric field is 1434.825 N/C

Direction is horizontally to the left

8 0
3 years ago
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