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melomori [17]
3 years ago
7

Energy sources can be placed in two categories: renewable and nonrenewable. How do you think these two energy sources differ fro

m each other?
Physics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Answer:

Renewable energy sources can come again, but nonrenewable is gone forever. For example, coal and gasoline are both nonrenewable.

Explanation:

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List four landforms created by wave erosion?
choli [55]
A Headland,a Sea Cave,a Sea Arch, and a sea cut cliff.
8 0
3 years ago
Susie rides down and to the right on a slide for a total displacement of -3m at an angle of 45 degrees above the ground. What wa
Svetlanka [38]

Susie's vertical displacement is 2.1 m

Explanation:

In order to solve this problem, we have to resolve the displacement vector along the vertical direction.

The vertical component of a vector is given by:

v_y = v sin \theta

where

v is the magnitude of the vector

\theta is the angle between the direction of the vector and the horizontal

Therefore, the vertical  component of the displacement in this problem is given by

d_y = d sin \theta

where

d = 3 m is the magnitude of the displacement

\theta=45^{\circ} is the angle between the  displacement and the horizontal

Substituting, we find

d_y = (3)(sin 45^{\circ})=2.1 m

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

6 0
4 years ago
Where is the near point of an normal eye when accidentally wear a contact lens with a power of +2.0 diopters?
Lerok [7]

Answer:

The near point of an eye with power of +2 dopters, u' = - 50 cm

Given:

Power of a contact lens, P = +2.0 diopters

Solution:

To calculate the near point, we need to find the focal length of the lens which is given by:

Power, P = \frac{1}{f}

where

f = focal length

Thus

f = \frac{1}{P}

f = \frac{1}{2} = + 0.5 m

The near point of the eye is the point distant such that the image formed at this point can be seen clearly by the eye.

Now, by using lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{u'}

where

u = object distance = 25 cm = 0.25 m = near point of a normal eye

u' = image distance

Now,

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

\frac{1}{u'} = \frac{1}{0.5} - \frac{1}{0.25}

\frac{1}{u'} = \frac{1}{f} - \frac{1}{u}

Solving the above eqn, we get:

u' = - 0.5 m = - 50 cm

7 0
3 years ago
Describe in brief the importance of measurement in our daily life?<br>​
Volgvan

Measurement tools make our lives safer and better? And they increase the quality and quantity of life. Arguably, the ability to measure calculating

physical properties accurately have tremendous survival value that gives humans adaptive, evolutionary advantages sharpened through many years of natural selection.

6 0
4 years ago
What is the difference between 1D motion and 2D motion?<br> I need explanation, pleases.
zaharov [31]

Explanation:

1D motion is motion in only one direction.  To put it simply, it's motion along a line.  For example, a train on a straight track has 1D motion.

2D motion is motion in two directions.  A good example of this is a projectile launched at an angle.  It has both vertical motion and horizontal motion.

5 0
3 years ago
Read 2 more answers
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