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I am Lyosha [343]
3 years ago
7

If you need to make 240 g lioh, how many grams of li3n must you react with excess water?

Chemistry
2 answers:
Savatey [412]3 years ago
8 0
Answer is: 116,1 g of Li₃N.
Chemical reaction: Li₃N + 3H₂O → 3LiOH + NH₃.
m(LiOH) = 240g.
n(LiOH) = m(LiOH) ÷ M(LiOH).
n(LiOH) = 240 g ÷ 24 g/mol = 10 mol.
from chemical reaction: n(LiOH) : n(Li₃N) = 3 : 1.
10 mol : n(Li₃N) = 3 : 1.
n(Li₃N) = 3,33 mol.
m(Li₃N) = n(Li₃N) · M(Li₃N)
m(Li₃N) = 3,33 mol · 34,85 g/mol = 116,1 g.
Juli2301 [7.4K]3 years ago
4 0

117 g would be the best bet for this question.


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How mamy moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess
Anestetic [448]

Answer:

3.62moles

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46g of Na produced 117g of NaCl.

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