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I am Lyosha [343]
3 years ago
7

If you need to make 240 g lioh, how many grams of li3n must you react with excess water?

Chemistry
2 answers:
Savatey [412]3 years ago
8 0
Answer is: 116,1 g of Li₃N.
Chemical reaction: Li₃N + 3H₂O → 3LiOH + NH₃.
m(LiOH) = 240g.
n(LiOH) = m(LiOH) ÷ M(LiOH).
n(LiOH) = 240 g ÷ 24 g/mol = 10 mol.
from chemical reaction: n(LiOH) : n(Li₃N) = 3 : 1.
10 mol : n(Li₃N) = 3 : 1.
n(Li₃N) = 3,33 mol.
m(Li₃N) = n(Li₃N) · M(Li₃N)
m(Li₃N) = 3,33 mol · 34,85 g/mol = 116,1 g.
Juli2301 [7.4K]3 years ago
4 0

117 g would be the best bet for this question.


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Determine the number of hydrogen atoms in the following compound 3Cu(C2H3O2)2
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Which new diagnosis would prompt the provider to discontinue a prn order for magnesium hydroxide? group of answer choices renal
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Renal failure is the new diagnosis that the provider would prompt to discontinue a PRN order for magnesium hydroxide.

<h3>What is Renal failure?</h3>

Renal failure is a special condition where the person is unable to manage the function of the kidney organ.

The magnesium hydroxide may cause renal failure because this salt must be eliminated by the kidney and therefore it may trigger health complications.

In conclusion, renal failure is the new diagnosis that the provider would prompt to discontinue a PRN order for magnesium hydroxide.

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It is found that a gas undergoes a first-order decomposition reaction. If the rate constant for this reaction is 8.1 x 10-2 /min
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Answer:

28.43 min

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 8.1\times 10^{-2} min⁻¹

Initial concentration [A_0] = 0.1 M

Final concentration [A_t] = 1.0\times 10^{-2} M

Time = ?

Applying in the above equation, we get that:-

1.0\times 10^{-2}=0.1e^{-8.1\times 10^{-2}\times t}

0.1e^{-8.1\times \:10^{-2}t}=10^{-2}

e^{-8.1\times \:10^{-2}t}=\frac{1}{10}

\ln \left(e^{-8.1\times \:10^{-2}t}\right)=\ln \left(\frac{1}{10}\right)

t=28.43\ min

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3 years ago
What volume of 0. 250 m sulfuric acid solution would be needed to react completely with 18. 00 ml of 0. 350 m ammonia solution?
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The volume of 0. 250 m sulfuric acid solution would be needed to react completely with 18. 00 ml of 0. 350 m ammonia solution is 0.0504 L.

The balance reaction is 2KOH+H_{2} SO_{4}=2H_{2} O+K_{2} SO_{4}

This shows us that we need 2 moles of KOH for each mole of sulfuric acid.

So, we write mathematically 2*(0.018*0.350)=(V*0.250)

V=(2*0.018*0.350)/0.250=0.0504 L

<h3>Sulfuric acid</h3>

With the chemical formula H2SO4, sulfuric acid, also known as sulphuric acid or oil of vitriol, is a mineral acid made up of the elements hydrogen, oxygen, and sulfur. It is a viscous liquid that is miscible with water and is colorless, odorless, and viscous.

Since pure sulfuric acid has a significant affinity for water vapor, it does not naturally occur on Earth; as a result, it is hygroscopic and rapidly collects water vapor from the atmosphere. Due to its potent dehydrating and oxidizing qualities, concentrated sulfuric acid is extremely corrosive to various materials, including rocks and metals. One significant exception is phosphorus pentoxide, which dehydrates sulfuric acid to sulfur trioxide instead of being dehydrated by sulfuric acid.

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6 0
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