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I am Lyosha [343]
2 years ago
7

If you need to make 240 g lioh, how many grams of li3n must you react with excess water?

Chemistry
2 answers:
Savatey [412]2 years ago
8 0
Answer is: 116,1 g of Li₃N.
Chemical reaction: Li₃N + 3H₂O → 3LiOH + NH₃.
m(LiOH) = 240g.
n(LiOH) = m(LiOH) ÷ M(LiOH).
n(LiOH) = 240 g ÷ 24 g/mol = 10 mol.
from chemical reaction: n(LiOH) : n(Li₃N) = 3 : 1.
10 mol : n(Li₃N) = 3 : 1.
n(Li₃N) = 3,33 mol.
m(Li₃N) = n(Li₃N) · M(Li₃N)
m(Li₃N) = 3,33 mol · 34,85 g/mol = 116,1 g.
Juli2301 [7.4K]2 years ago
4 0

117 g would be the best bet for this question.


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Answer:

Explanation:

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Provide a stepwise synthesis of 1-cyclopentylethanamine using the Gabriel synthesis. Collapse question part Testbank, Question 0
ra1l [238]

Answer:

Azide synthesis is the first method on the table of synthesis of primary amines. The Lewis structure of the azide ion, N3−, is as shown below.

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imide linkage

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Answer:

The object placed in the water has a volume of 19 cm³

Explanation:

<u>Step 1: </u>Data given

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