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3 years ago

If you need to make 240 g lioh, how many grams of li3n must you react with excess water?

2 answers:

8 0

Answer is: 116,1 g of Li₃N.
Chemical reaction: Li₃N + 3H₂O → 3LiOH + NH₃.
m(LiOH) = 240g.
n(LiOH) = m(LiOH) ÷ M(LiOH).
n(LiOH) = 240 g ÷ 24 g/mol = 10 mol.
from chemical reaction: n(LiOH) : n(Li₃N) = 3 : 1.
10 mol : n(Li₃N) = 3 : 1.
n(Li₃N) = 3,33 mol.
m(Li₃N) = n(Li₃N) · M(Li₃N)
m(Li₃N) = 3,33 mol · 34,85 g/mol = 116,1 g.

Juli2301 [7.4K]3 years ago

4 0

117 g would be the best bet for this question.

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For each of the bonds listed, tell which atom is more negatively charged a. C--H b. C--N c. C--S d. C--O

blondinia [14]

Explanation:

The atom is considered to be more electronegative , when it has the tendency to get a slight negative i.e. , delta negative charge on it , and the other atom gets a delta positive charge .

In the periodic table ,

As we go left to right in the periodic table , the electronegativity increases ,

and

As we go top to bottom , the electronegativity decreases .

Hence , from the option given in the question ,

a. C--H , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , Carbon is more electronegative than hydrogen .

b. C--N , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , nitrogen is more electronegative than Carbon .

c. C--S , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , sulfur is more electronegative than Carbon .

d. C--O , the electronegativity of both the atom is almost the same , but looking at the treads of the periodic table , oxygen is more electronegative than Carbon .

5 0

3 years ago

Water molecules that remain in a fixed position with very little motion would be characteristic of

Dominik [7]

Ice because the molecules have less movement in solids

6 0

3 years ago

The element Osminum has a density of 22.6 g/cm3. the mass of a block of Osmium with three sides of 1.01cmx0.223 cm x 0.648 cm is

Alika [10]

Volume of osmium = 1.01(0.223)(0.648) = 0.14595 cm3

Density = mass / volume
So density x volume = mass of osmium
22.6 x 0.14595 = 3.29845 g

6 0

3 years ago

Human organ systems work together in many ways. Which statement accurately explains the relationship between two body systems?A.

melomori [17]

Answer:

Option D. The nervous system regulates the movement of the muscular system.

Explanation:

The nervous system regulates the movement of the muscles as they receive signals from both the brain and nerve cells

4 0

3 years ago

Whats the voltage of CuCl2 + Zn -> ZnCl2 + Cu

gtnhenbr [62]

Answer:

Approximately $1.10\; {\rm V}$ under standard conditions.

Explanation:

Equation for the overall reaction:

${\rm CuCl_{2}}\, (aq) + {\rm Zn}\, (s) \to {\rm ZnCl_{2}} \, (aq) + {\rm Cu}\, (s)$ .

Write down the ionic equation for this reaction:

$\begin{aligned}& {\rm Cu^{2+}}\, (aq) + 2\; {\rm Cl^{-}}\, (aq) + {\rm Zn}\, (s)\\ & \to {\rm Zn^{2+}} \, (aq) + 2\; {\rm Cl^{-}}\, (aq) + {\rm Cu}\, (s)\end{aligned}$ .

The net ionic equation for this reaction would be:

${\rm Cu^{2+}}\, (aq) + {\rm Zn}\, (s) \to {\rm Zn^{2+}}\, (aq) + {\rm Cu}\, (s)$ .

In this reaction:

Zinc loses electrons and was oxidized (at the anode): ${\rm Zn}\, (s) \to {\rm Zn^{2+}}\, (aq) + 2\, {\rm e^{-}}$ .
Copper gains electrons and was reduced (at the cathode): ${\rm Cu^{2+}}\, (aq) + 2\, {\rm e^{-}} \to {\rm Cu} \, (s)$ .

Look up the standard potentials for each half-reaction on a table of standard reduction potentials.

Notice that ${\rm Zn}\, (s) \to {\rm Zn^{2+}}\, (aq) + 2\, {\rm e^{-}}$ is oxidation and is likely not on the table of standard reduction potentials. However, the reverse reaction, ${\rm Zn^{2+}}\, (aq) + 2\, {\rm e^{-}} \to {\rm Zn}\, (s)$ , is reduction and is likely on the table.

$E(\text{anode}) = -0.7618\; {\rm V}$ for ${\rm Zn^{2+}}\, (aq) + 2\, {\rm e^{-}} \to {\rm Zn}\, (s)$ , and
$E(\text{cathode}) = 0.3419\; {\rm V}$ for ${\rm Cu^{2+}}\, (aq) + 2\, {\rm e^{-}} \to {\rm Cu} \, (s)$ .

The reduction potential of ${\rm Zn}\, (s) \to {\rm Zn^{2+}}\, (aq) + 2\, {\rm e^{-}}$ would be $-E(\text{anode}) = -(-0.7618\; {\rm V}) = 0.7618\; {\rm V}$ , the opposite of the reverse reaction ${\rm Zn^{2+}}\, (aq) + 2\, {\rm e^{-}} \to {\rm Zn}\, (s)$ .

The standard potential of the overall reaction would be the sum of the standard potentials of the two half-reactions:

$\begin{aligned} E^{\circ} &= E^{\circ}(\text{cathode}) + (-E^{\circ}(\text{anode})) \\ &= 0.3419 - (-0.7618\; {\rm V}) \\ &\approx 1.10\; {\rm V}\end{aligned}$ .

7 0

2 years ago