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mamaluj [8]
3 years ago
12

Kinetic Energy Problems = KE = 0.5m x 12

Chemistry
1 answer:
Brut [27]3 years ago
8 0

Explanation:

The kinetic energy of an object is given by :

K=\dfrac{1}{2}mv^2

1. Mass, m = 5 kg

Speed, v = 2 m/s

K_1=\dfrac{1}{2}\times 5\times (2)^2\\\\=10\ J

2. Mass, m = 71 kg

Speed, v = 1 m/s

K_2=\dfrac{1}{2}\times 71\times (1)^2\\\\=35.5\ J

3.  Mass, m = 71 kg

Speed, v = 5 m/s

K_3=\dfrac{1}{2}\times 71\times (5)^2\\\\=887.5\ J

4. Mass, m = 1816 kg

Speed, v = 25 m/s

K_4=\dfrac{1}{2}\times 1816\times (25)^2\\\\=567500\ J

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The explanation for the large space between particles in a gas is provided by ____. A. Boyle's law B. Dalton's law C. kinetic th
NeTakaya

The explanation for the large space between particles in a gas is provided by the kinetic theory (option C).

<h3>What is the kinetic theory?</h3>

The kinetic theory is a scientific theory used in physics to understand the behavior of gases.

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In conclusion, the explanation for the large space between particles in a gas is provided by the kinetic theory (option C).

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2 years ago
If a house viewed through infrared goggles ,where would the most seen
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The answer is D - near the roof.

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5 0
3 years ago
How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac
Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

,

• using the molar mass of Ca(OH)2 (74g/mol).

,

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

,

• using the molar mass of HNO3 (63.02g/mol).

4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3

So, 7.32g of HNO3 are required.

4 0
2 years ago
What is the molarity of an H3PO4solution if 15.0 mL is completely neutralized by 38.5 mL of 0.150 MNaOH? Please explain your ans
rodikova [14]

Answer:

M=Molarity

V=volume

change millilitre to litre

so:15ml=0.015 L

:38.5ml=0.0385 L

M1V1=M1V1

M1* 0.015 L= 0.15M*0.0385 L

M1=0.00385

8 0
4 years ago
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