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3 years ago

Which property of a mineral sample does not influence how quickly it settles in water? 1) density 2) hardness 3) shape 4) size

Chemistry

1 answer:

satela [25.4K]3 years ago

8 0

<h3><u>Answer</u>;</h3>

4) size

<h3><u>Explanation</u>;</h3>

The mineral’s physical properties are used in identifying minerals and are determined by its chemical composition and crystal structure.
<u>Streak</u> is the color of the mineral in powdered form and since it is a more accurate illustration of the mineral’s color, its is a more reliable property of minerals than color for identification.
<u>Hardness</u> is one of the better properties of minerals to use for identifying a mineral. Hardness is a measure of the mineral’s resistance to scratching.
<u>Density</u> may be used to identify minerals. It is used to describe the amount of matter in a certain amount of space. Substances that have more matter packed into a given space have higher densities.

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4 years ago

What volume of a concentrated HCl solution, which is 36.0% HCl by mass and has a density of 1.179 g/mL, should be used to make 4

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Answer:

130ml of HCl(36%) in 4.90L solution => pH = 1.50

Explanation:

Need 4.90L of HCl(aq) solution with pH = 1.5.

Given pH = 1.5 => [H⁺] = 10⁻¹·⁵M = 0.032M in H⁺

[HCl(36%)] ≅ 12M in HCl

(M·V)concentrate = (M·V)diluted

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3 years ago

Calculate the pH of the following simple solutions:

IceJOKER [234]

Answer :

(1) pH = 1.27

(2) pH = 13.35

(3) The given solution is not a buffer.

Explanation :

Concentration of HCl = $53.1mM=53.1\times 10^{-3}M$

As HCl is a strong acid. So, it dissociates completely to give hydrogen ion and chloride ion.

So, Concentration of hydrogen ion= $53.1\times 10^{-3}M$

pH : It is defined as the negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$pH=-\log (53.1\times 10^{-3})$

$pH=1.27$

Concentration of KOH = 0.223 M

As KOH is a strong base. So, it dissociates completely to give hydroxide ion and potassium ion.

So, Concentration of hydroxide ion= 0.223 M

Now we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (0.223)$

$pOH=0.65$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-0.65=13.35$

Buffer : It is defined as a solution that maintain the pH of the solution by adding the small amount of acid or a base.

It is not a buffer because HCl is a strong acid and KOH is a strong base. Both dissociates completely.

As we know that the pH of strong acid and strong base solution is always 7.

So, the given solution is not a buffer.

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