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3 years ago

HELP ME PLZ ITS REALLY IMPORTANT! PLEASE TRY TO DO ALL!!

Chemistry

1 answer:

poizon [28]3 years ago

7 0

1. holding a tray in the cafeteria line
2.
3. joule divided by a second
4.
5. the force a simple machine applies to an object

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What is the main function of the muscular system A. digestion B. breathing C.movement D. Eliminating

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Answer:

C, Movement

Explanation:

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3 years ago

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Given 50g and 27ml find density

Airida [17]

Answer:

1.85g per cubic centimeter (g/cm3

Explanation:

because density=mass/volume, so it will be 50g divide by 27ml =. 1.85g/cm3

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1 year ago

What is the percentage of hydrogen in c2h4

jarptica [38.1K]

Ethylene- C2H4 = 85.7% Carbon and 14.3% Hydrogen

Find the atomic masses for each element and multiply it by the number of atoms in the compound, then add.

C- 12.0 * 2= 24.0

H- 1.00 * 4= 4.00

-----------------------

28.0

Take the masses for each element and divide it by the total mass. Then change the answer to get the percent.

C 24.0 / 28.0= .857 = 85.7%

H 4.00 / 28.0= .143 = 14.3%

<h3>Ethylene is 85.7% Carbon and 14.3% Hydrogen </h3>

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3 years ago

The trend of this graph is<br><br><br> a. Negative<br><br><br> b. Positive<br><br><br> c. Zero

Sveta_85 [38]

B. positive because y increases as x does. It it were negative y would decrease as x increases and it would be 0 if y stayed the same as x increases.

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3 years ago

Answer the following questions…

Zina [86]

The concentration of the hydronium ion in hydrochloric acid is 0.0045 M, and the pH of the solution is 2.34.

pH is the potential of the hydrogen or the hydronium ions in the aqueous solution.

As the solution contains $4.5 \times 10^{-3} \;\rm M\;$ HCl the concentration of the hydronium ion will be the same, $4.5 \times 10^{-3} \;\rm M.$

The pH of the solution is calculated as:

$\begin{aligned} \rm pH &= \rm -log[H^{+}]\\\\&= - \rm log (4.5 \times 10^{-3})\\\\&= 2.34\end{aligned}$

The concentration of the hydroxide ion is calculated from pH and hydronium ion as:

$\begin{aligned} \rm [H_{3}O^{+}][OH^{-}] &= 10^{-14}\\\\&= \dfrac{1 \times 10^{-14}}{4.5 \times 10^{-3}}\\\\&= 2.2 \times 10^{12}\end{aligned}$

Now, for the calcium hydroxide solution, the calculations are shown as,

$\begin{aligned} \rm (H_3}\rm O^{+}) &= \rm antilog (-pH)\\\\&= \rm antilog (-8)\\\\&= 10^{-8} \;\rm M\end{aligned}$

pOH is calculated as:

$\begin{aligned} \rm pOH &= 14- 8 = 6\\\\\rm [OH^{-}] &= \rm antilog (-6)\\\\&= 10^{-6} \end{aligned}$

The concentration of calcium hydroxide is calculated as:

$\begin{aligned} &= \dfrac{1}{2} \times \rm [OH^{-}]\\\\&= 5 \times 10^{-4} \;\rm M\end{aligned}$

Therefore, the pH and the pOH give the concentration of the hydrogen or the hydronium ion and the hydroxide ion.

Learn more about pH and pOH here:

brainly.com/question/16062632

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3 0

2 years ago