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diamong [38]
3 years ago
6

HELP ME PLZ ITS REALLY IMPORTANT! PLEASE TRY TO DO ALL!!

Chemistry
1 answer:
poizon [28]3 years ago
7 0
1. holding a tray in the cafeteria line
2.
3. joule divided by a second
4. 
5. the force a simple machine applies to an object
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The information below is a description of a substance:
skelet666 [1.2K]

Answer:

A chemical change

Explanation:

7 0
3 years ago
Which state of matter has a definite volume but can change its shape?
sashaice [31]

Answer:

solid

Explanation:

because solid has a definite shape and volume

5 0
3 years ago
Read 2 more answers
Identify the decay mode of hydrogen -3.
Phantasy [73]

Answer:

The radioactive decay mode that does not result in a different nuclide is gamma decay. In gamma decay, the only product is a gamma ray photon.

Explanation:

5 0
2 years ago
If you start with 4.5 moles of aluminum and 6.5 moles of copper chloride to make aluminum chloride and copper, what is the limit
Alex Ar [27]

Answer:

The limiting reagent is CuCl

Explanation:

The initial number of moles of aluminum, Al = 4.5 moles

The number of moles of copper, Cu = 6.5 moles

The given chemical reaction is presented as follows;

2Al + 3CuCl → 2AlCl₃ + 3Cu

Therefore, we have, 2 moles of aluminum combine with 3 moles of CuCl produces 2 moles of AlCl₃ and 3 moles of Cu

1 mole of Al will combine with (3/2) moles of CuCl,

Therefore, 4.5 moles of Al will combine with (4.5 × (3/2) = 6.75) 6.75 moles of CuCl

Given that the number of moles of CuCl present is only 6.5 moles which is less than the 6.75 moles required to combine with the 4.5 moles, the 6.5 moles of CuCl limits the amount of AlCl₃ and Cu produced, and therefore the CuCl is the limiting reagent.

8 0
3 years ago
If 45.0 mL of 6.00M HCl is added to 130 mL of H2O, Determine the molarity of the final solution. (show work)
Ivahew [28]

2.07 M is the molarity of the final solution if 45.0 ml of 6.00M HCl is added to 130 ml of H_{2}O.

Explanation:

Data given:

volume of HCl, V1 = 45 ml

molarity of the HCl solution, M1 = 6 M

final volume of the HCl solution after water is added, V2 = 130 ml

final molarity M2 =?

After the dilution, the molarity of the new solution can be found by using the formula:

M1V1 = M2V2

here M1 and V1 are the molarity and volume for concentrated solution, M2 and V2 represents the diluted solution's molarity and volume.

Applying the formula after rearranging the equation, we get

M2 = \frac{M1V1}{V2}

M2 = \frac{6X45}{130}

M2 = 2.07 M

The final molarity of the HCl solution is 2.07 M

4 0
4 years ago
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