Answer:
Heptane > hexane> 3,3-dimethylpentane > butane
Explanation:
All things being equal, it is expected that the boiling point of the members of the alkane homologous series increase as we move down the group.
Hence for example, butane is expected to have a higher boiling point than ethane. Another important factor we would be considering in this answer is the presence of a branched alkane amongst the answers in the question. A straight-chain alkane will have a boiling point which is higher than that of a branched-chain alkane due to the greater surface area in contact, thus the greater van der Waals forces, between adjacent molecules
Now if we are to rank the compounds on the basis of boiling point, the answer is as follows:
Heptane > hexane > 3,3-dimethylpentane> butane
Answer:
52.17%
Explanation:
COCl2.6H20
C=12,O=16,Cl=35.5,H=1
Relative molecular mass of COCl2.6H2O= 12+16+71+6(2+16) = 99 + 108= 207g
Relative molecular mass of 6H2O = 108g
Percentage of water = (108/207 )*100
= 52.17%
Answer: Mg is the excess reactant for the forward reaction.
Explanation: It is a stoichiometry problem and solved with the help of given grams and using balanced equation. Grams of both the reactants are converted to moles and divided by their coefficients. The excess reactant is the one for which we get the highest number on doing above steps.
The balanced equation is:
Molar mass of silicon tetra chloride is 169.9 gram per mol and the molar mass of Mg is 24.3 gram per mol.
= 
= 2.67 mol Mg
From balanced equation, the coefficient of silicon tetra chloride is 1 and that of Mg is 2. So, we will divide the moles of silicon tetra chloride by 1 and that of Mg by 2 and see which one gives highest number.
For silicon tetra chloride, 
= 0.317
and for Mg, 
= 1.34
The highest number is for Mg and so the excess reactant for the forward reaction is Mg.
Answer:
9.91 mL
Explanation:
Using the combined gas law equation as follows;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (torr)
P2 = final pressure (torr)
V1 = initial volume (mL)
V2 = final volume (mL)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question;
V1 = 15.0mL
V2 = ?
P1 = 760 torr
P2 = 1252 torr
T1 = 10°C = 10 + 273 = 283K
T2 = 35°C = 35 + 273 = 308K
Using P1V1/T1 = P2V2/T2
760 × 15/283 = 1252 × V2/308
11400/283 = 1252V2/308
Cross multiply
11400 × 308 = 283 × 1252V2
3511200 = 354316V2
V2 = 3511200 ÷ 354316
V2 = 9.91 mL
