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2 years ago

How does the mass of jupiter compare to the rest of the planets in the solar system?

Physics

1 answer:

katen-ka-za [31]2 years ago

3 0

It is the most massive planet in the solar system.

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2. A truck speeds up from a velocity of 6 m/s to 14 m/s in 4 seconds. What is the trucks acceleration? SHOW YOUR WORK

zavuch27 [327]

As it is given here

initial speed is

$v_i = 6 m/s$

After 4 seconds the final speed is

$v_f = 14 m/s$

so here we can use the formula of acceleration using kinematics

$a = \frac{v_f - v_i}{t}$

$a = \frac{14 - 6}{4}$

$a = 2 m/s^2$

so here it will accelerate at 2 m/s^2 rate.

As it is given here

initial it starts from rest

$v_i = 0 m/s$

After 2.5 seconds the final speed is

$v_f = 15 m/s$

so here we can use the formula of acceleration using kinematics

$a = \frac{v_f - v_i}{t}$

$a = \frac{15 - 0}{2.5}$

$a = 6 m/s^2$

so here it will accelerate at 6 m/s^2 rate.

i think question is not correct as in first line it is saying about a bag of trash and then in next line it is asking for the position of Jumper and bridge.

7 0

2 years ago

A car weighing 12,000 N is parked on a 36° slope. The car starts to roll down the hill. What is the acceleration of the car?

Delicious77 [7]

Answer: 5.8 m/s squared

Explanation: just got that question lol

4 0

2 years ago

10. In Freudian theory, which one of the following is an example of a Thanatos instinct, which includes aggression, trauma, and

Lelechka [254]

D substance abuse :) hope this helps

8 0

1 year ago

Points A, B, and C form the vertices of a triangle in a nonuniform electrostatic field. The electrostatic work done on a particl

Trava [24]

Answer:

Explanation:

Let electric potential at A ,B and C be Va , Vb and Vc respectively.

Work done = charge x potential difference

Wab = q ( Va - Vb )

Wac = q ( Va - Vc )

Given

Wac = - Wab / 3

3Wac = - Wab

Now

Wbc = q ( Vb - Vc )

= q [ ( Va-Vc ) - ( Va - Vb )]

= Wac - Wab

= Wac + 3Wac

= 4Wac

4 0

2 years ago

What is the electric potential, i.e. the voltage, 0.30 m from a point charge of 6.4 x 10-C?

Gwar [14]

Answer:

V = 192 kV

Explanation:

Given that,

Charge, $q=6.4\times 10^{-6}\ C$

Distance, r = 0.3 m

We need to find the electric potential at a distance of 0.3 m from a point charge. The formula for electric potential is given by :

$V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6.4\times 10^{-6}}{0.3}\\\\V=192000\ V\\\\V=192\ kV$

So, the required electric potential is 192 kV.

3 0

2 years ago