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2 years ago

Can someone help me w this ?

Physics

1 answer:

lukranit [14]2 years ago

7 0

Answer:

i can't sorry

Explanation:

I didn't really pay attention in that class

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8. At what position does the mass have the greatest acceleration?

gulaghasi [49]

Answer:

Option (e)

Explanation:

If a mass attached to a spring is stretched and released, it follows a simple harmonic motion.

In simple harmonic motion, velocity of the mass will be maximum, kinetic energy is maximum and acceleration is 0 at equilibrium position (at 0 position).

At position +A, mass will have the minimum kinetic energy, zero velocity and maximum acceleration.

Therefore, Option (e) will be the answer.

6 0

2 years ago

an automobile has a tire pressure of 325 kpa when the temperature is 10°C of the temperature rises to 50°C what is the new press

Finger [1]

Old temperature = 283 K.
New temp = 323 K.

(323/283) x (325 kPa) = 371 kPa.

8 0

2 years ago

Thought Experiment: A monkey escapes from a zoo and climbs a tree. After failing to entice the monkey down, a zookeeper fires a

Andreyy89

Explanation:

When bullet is shot towards the monkey then let say the distance of monkey from the bullet is "d"

so we can find the time to reach the bullet to the monkey

$t = \frac{d}{vcos\theta}$

Now similarly we can find the vertical displacement of the bullet in the same time

$\Delta y = vsin\theta t - \frac{1}{2}gt^2$

$\Delta y = v sin\theta (\frac{d}{vcos\theta}) - \frac{1}{2}gt^2$

so it is given as

$\Delta y = d tan\theta - \frac{1}{2}gt^2$

here if the monkey is initially at height H above the ground at given angle then we can say

$H = dtan\theta$

so we can say that

$\Delta y = H - \frac{1}{2}gt^2$

So if at the same time monkey will fall down then the height of monkey from ground after time "t" is given as

$\Delta y = H - \frac{1}{2}gt^2$

so here bullet will hit the monkey as both monkey and bullet are at same position.

3 0

2 years ago

An 1120 kg car traveling at 17.2 m/s is brought to a stop while skidding 40m. Calculate the work done on the car by the friction

Nesterboy [21]

Answer:

Work = 165670.4 J = 165.67 KJ

Explanation:

First, we will find the deceleration of the car, using the 3rd equation of motion:

$2as = v_{f}^2 - v_{i}^2\\$

where,

a = deceleration = ?

s = skid distance = 40 m

vf = final speed = 0 m/s

vi = initial speed = 17.2 m/s

Therefore,

$2a(40\ m) = (0\ m/s)^2 - (17.2\ m/s)^2\\a = - 3.698\ m/s^2$

the negative sign indicates deceleration here.

Now, we will calculate the braking force applied by the brakes on the car:

$F = ma\\F = (1120\ kg)(-3.698\ m/s^2)\\F = - 4141.76\ N$

the negative sign indicates braking force.

Now, we will calculate the work done using the magnitude of this force:

$Work = |F|s\\Work = (4141.76\ N)(40\ m)\\$

8 0

2 years ago

What Device can be used to increase voltage from a source of direct-current?

Rudiy27

Multi meter reading instruments Device can be used to increase voltage know direct-current

4 0

2 years ago