B. The number of field lines on the source charge.
The magnitude of other charge will be 1 × 10⁻² coulomb
The formula of electrostatic force is
Electrostatic force = K q1 q1 / r²
where k is the coulomb's constant whose value is 9 × 10⁹
q1 and a2 are the magnitude of charges
and r is the distance between them
magnitude of the force given to us is 9.0 × 10⁻⁵ newtons
magnitude of one charge = 1.0 × 10⁻⁶ coulomb
Force = K q1 q2 / r²
9.0 × 10⁻⁵ = ( ( 9 × 10⁹ ) × ( 1.0 × 10⁻⁶ ) × q2 ) / 1
9.0 × 10⁻⁵ = 9 × 10³ × q2
10⁻² = q2
Charge on q2 is 1 × 10⁻² coulomb
So the magnitude of the second charge is came out to be 1 × 10⁻² coulomb after applying the formula of electrostatic force.
Learn more about electrostatic force here:
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Answer:
Specific heat at constant pressure is = 1.005 kJ/kg.K
Specific heat at constant volume is = 0.718 kJ/kg.K
Explanation:
given data
temperature T1 = 50°C
temperature T2 = 80°C
solution
we know energy require to heat the air is express as
for constant pressure and volume
Q = m × c × ΔT ........................1
here m is mass of the gas and c is specific heat of the gas and Δ
T is change in temperature of the gas
here both Mass and temperature difference is equal and energy required is dependent on specific heat of air.
and here at constant pressure Specific heat is greater than the specific heat at constant volume,
so the amount of heat required to raise the temperature of one unit mass by one degree at constant pressure is
Specific heat at constant pressure is = 1.005 kJ/kg.K
and
Specific heat at constant volume is = 0.718 kJ/kg.K
The farther the distance, the weaker the gravitational force
