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Answer:
a= - 6.667 m/s²
Explanation:
Given that
The initial speed of the box ,u= 20 m/s
The final speed of the box ,v= 0 m/s
The distance cover by box ,s= 30 m
Lets take the acceleration of the box = a
We know that
v²= u ² + 2 a s
Now by putting the values in the above equation we get
0²=20² + 2 a x 30
a= - 6.667 m/s²
Negative sign indicates that velocity and acceleration are in opposite direction.
Therefore the acceleration of the box will be - 6.667 m/s² .
Missing questions: "find the speed of the electron".
Solution:
the magnetic force experienced by a charged particle in a magnetic field is given by
where
q is the particle charge
v its velocity
B the magnitude of the magnetic field
the angle between the directions of v and B.
Re-arranging the formula, we find:
and by substituting the data of the problem (the charge of the electron is
), we find the velocity of the electron:
Solution:
the magnetic force experienced by a charged particle in a magnetic field is given by
where
q is the particle charge
v its velocity
B the magnitude of the magnetic field
Re-arranging the formula, we find:
and by substituting the data of the problem (the charge of the electron is