El unico que se es el del oxígeno: o2
Answer:
Explanation:
Given
mass of ice 
Final temperature of liquid 
Specific heat of water 
Latent heat of fusion 
Latent heat of vaporization 
Suppose M is the mass of steam at 
Heat required to melt ice and convert it to water at 

Heat released by steam

and
must be equal as the heat gained by ice is equal to Heat released by steam


![\Rightarrow M=\dfrac{m[L+c\times T_f]}{L_v+c(100-T_f)}](https://tex.z-dn.net/?f=%5CRightarrow%20M%3D%5Cdfrac%7Bm%5BL%2Bc%5Ctimes%20T_f%5D%7D%7BL_v%2Bc%28100-T_f%29%7D)
![\Rightarrow M=\dfrac{119[333\times 10^3+4186\times 57]}{2256\times 10^3+4186\times (100-57)}](https://tex.z-dn.net/?f=%5CRightarrow%20M%3D%5Cdfrac%7B119%5B333%5Ctimes%2010%5E3%2B4186%5Ctimes%2057%5D%7D%7B2256%5Ctimes%2010%5E3%2B4186%5Ctimes%20%28100-57%29%7D)


The distance the object travels
No because it is dense and opaque
Answer:
The minimum speed required is 2.62m/s
Explanation:
The value of gravitational acceleration = g = 9.81 m/s^2
Radius of the vertical circle = R = 0.7 m
Given the mass of the pail of water = m
The speed at the highest point of the circle = V
The centripetal force will be needed must be more than the weight of the pail of water in order to not spill water.
Below is the calculation:



