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irina1246 [14]
3 years ago
13

Help What is Gravitational Potenial Energy

Physics
1 answer:
frosja888 [35]3 years ago
5 0
Gravitational potential energy is an object that possesses because of its position in a gravitational field
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The impulse given to a ball with massb of 2kg is 16 Ns. if the ball starts grin the rest, what is its final velocity?
Ainat [17]
B because it will not be any thing else

6 0
3 years ago
How much water is displaced by a solid object with a volume of 9 cm3 that is completely submerged in the water?
Sati [7]

Given :

An object with a volume of 9 cm³ is completely submerged in the water.

To Find :

How much water is displaced by the object.

Solution :

According to Archimedes' principle, the amount of volume displaced of fluid when an object is fully and partially submerged into that is equal to the volume of the object below the surface of liquid.

Now, it is given that object is fully submerged into water.

Therefore, volume of water displaced by the object is 9 cm³.

6 0
2 years ago
PLZ HELP I DON'T UNDERSTAND!! a boy is playing catch with his friend. He throws the ball straight up. When it leaves his hand, t
algol13

Explanation:

The mass of a ball, m = 2 kg

It is traveling with a speed of 10 m/s

The ball's kinetic energy just as it leaves the boy's hand is calculated as follows :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 2\times (10)^2\\\\=100\ J

The ball's kinetic energy just as it leaves the boy's hand is 100 J. The potential energy of the ball when it reaches the highest point is same as the kinetic energy as it leaves the boy's hand.

Hence, the required kinetic and potential energy is 100 J.

6 0
3 years ago
When an atom loses an electron, it becomes a
mel-nik [20]
When an atom loses an electron, it becomes a positive ion.

a. positive ion.
4 0
3 years ago
The electric field 2.8 cm from a small object points toward the object with a strength of 180,000 N/C. What is the object's char
Sonbull [250]

Answer:

2.1×10¹⁸ C

Explanation:

Using,

E = kq/r²...................... Equation 1

Where E = Electric field, q = charge, r = distance, k = coulombs constant.

make q the subject of the equation

q = Er²/k.................. Equation 2

Given: E = 180000 N/C, r = 2.8 cm = 0.028 m

Constant: k = 9×10⁹ Nm²/C².

Substitute these values into equation 2

q = 180000(9×10⁹)/0.028²

q = 2.1×10¹⁸ C

Hence the object charge is 2.1×10¹⁸ C

4 0
3 years ago
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