All categories

3 years ago

Tudy the images about geologic time.

Physics

2 answers:

Inessa [10]3 years ago

8 0

Answer:

The first flowering plants appeared in the Mesozoic era, not the Paleozoic era.

Explanation:

The Mesozoic era was an era where numerous organisms started to develop in very unique and more advanced ways, both the animals and the plants. In the last period of the Mesozoic, the Cretaceous, the first flowering plants started to appear on the scene. This was revolutionary trait of the plants, and soon these plants started to occupy more and more space and became one of the dominant organisms on the planet. Other important evolution that took place in this period are the appearance of the dinosaurs and the mammals, both becoming the dominant animals on the planet, first the dinosaurs, after that the mammals.

Natasha2012 [34]3 years ago

5 0

Answer:

Use the drop-down menus to match each description to the geologic era it describes.

The first birds and flowering plants appeared during this era. This is also when the most well-known dinosaurs lived.

✔ Mesozoic

Mammals, including humans, emerged during this era.

✔ Cenozoic

At the beginning of this era, animals lived only in water. By the end, some early dinosaurs emerged.

✔ Paleozoic

Explanation

You might be interested in

What does it mean standard unit?

Goshia [24]

Answer:

<h3>Standard unit is a standard measure that remains the same whenever, wherever and by whoever it is used. eg: The standard unit of time is second.</h3>

7 0

3 years ago

3V battery is used with a 15 ohm resistance.What is the current?

Pavlova-9 [17]

Answer:

0.2 A

Explanation:

V= IR

3 = I × 15

I = 3/15

= 1/5 = 0.2 A

5 0

3 years ago

Joey, whose mass is m = 36 kg, stands at rest at the outer edge of a frictionless merry-go-round with the mass M = 300 kg and th

Evgen [1.6K]

Answer:

$\omega=0.24\ rad.s^{-1}$

Explanation:

Given:

mass of person, $m=36\ kg$

mass of merry go-round, $M=300\ kg$

radius of merry go-round, $R=2\ m$

velocity of the person running, $v=4\ m.s^{-1}$

<u>We consider merry go-round as a ring:</u>

Now the moment of inertial of the ring is given as,

$I=M.R^2$

$I=300\times 2^2$

$I=1200\ kg.m^{-2}$

<u>Moment of inertia of the person considering as a point mass:</u>

$I_p=m.R^2$

$I_p=36\times 2^2$

$I_p=144\ kg.m^2$

<u>Now according to the conservation of angular momentum:</u>

$I.\omega=I_p.\omega_p$

where:

$\omega =$ angular velocity of the merry-go-round

$\omega_p=$ angular velocity of the person running

$1200\times \omega=144\times \frac{v}{R}$

$\omega=\frac{144}{1200} \times \frac{4}{2}$

$\omega=0.24\ rad.s^{-1}$

4 0

4 years ago

Read 2 more answers

My Notes A container is divided into two equal compartments by a partition. One compartment is initially filled with helium at a

Ostrovityanka [42]

Answer:

$final-temperature = T_{f} = 252.51K$

Explanation:

we can solve this problem by using the first law of thermodynamics.

$\Delta U= Q-W$

Q= heat added

U= internal energy

W= work done by system

$E_{final}= E_{initial}$

$C_{v}(N_{2})=1.04\frac{KJ}{Kg K}$

$C_{v}(He)=5.193\frac{KJ}{Kg K}$

now

From equation 1

$T_{f}=\frac{C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}}{C_{v} (N_{2}) C_{v}(He)}$

$T_{f} = \frac{315\times1.04+5.193\times240}{1.04+5.193}$

$T_{f} = 252.51K$

4 0

4 years ago

Estimate under what set of conditions it is possible, despite the spherical shape of the working electrode, to use linear diffus

goldfiish [28.3K]

When the experimental measurements diverge at very low values of the voltages. When the ratio of current to saturated current is very small. That is, i/I less than or equal to 1/100. When there is a finite current at Voltage

V = 0

Diffusion will have influence on current - voltage curve in the working electrode which is ionization detector.

The estimation under set of conditions that is possible, despite the spherical shape of the working electrode, to use linear diffusion equations to theoretically predict the current vs voltage curve expected in this experiment will be:

When the experimental measurements diverge at very low values of the voltages
when the ratio of current to saturated current is very small. That is, i/I less than or equal to 1/100
When there is a finite current at Voltage V = 0

Where

i = electric current

I = saturated current

V = voltage supplied

The curve expected will therefore give exponential curve from positive to negative domain because of the diffusion of ions from different directions

Learn more here: brainly.com/question/23985719

8 0

3 years ago