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3 years ago

How do I calculate the molecular weight of Mg(OH)2?

Chemistry

1 answer:

vodomira [7]3 years ago

5 0

The molecular weight of Mg(OH)2 : 58 g/mol

<h3>Further explanation</h3>

Given

Mg(OH)2 compound

Required

The molecular weight

Solution

Relative atomic mass (Ar) of element : the average atomic mass of its isotopes

Relative molecular weight (M) : The sum of the relative atomic mass of Ar

M AxBy = (x.Ar A + y. Ar B)

So for Mg(OH)2 :

= Ar Mg + 2 x Ar O + 2 x Ar H

= 24 g/mol + 2 x 16 g/mol + 2 x 1 g/mol

= 24 + 32 + 2

= 58 g/mol

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he combustion of propane (C3H8) is given by the balanced chemical equation C_3H_8+5O_2\longrightarrow3CO_2+4H_2O C 3 H 8 + 5 O 2

Basile [38]

Answer:

290 grams

Explanation:

Let's begin by writing the balanced chemical equations:

$C_{3}H_{8} +5O_{2} --->3CO_{2} +4H_{2}O$

Then we calculate the number of moles in 97g of propane.

n(propane)= $\frac{mass}{molarmass} =\frac{97g}{44.1g/mol}=2.1995mol$

According to the balanced chemical equation, one mole of propane produces 3 moles of carbon dioxide. So the available number of moles of propane must be multiplied by three to work out the number of carbon dioxide produced.

n(carbon dioxide)= 2.1995mol*3 = 6.5985mol

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4 0

3 years ago

Determine the empirical and molecular formula:

Bingel [31]

Answer:

The empirical formula = molecular formula = C13H18O2

Explanation:

in 100% compound we have 75.6 % Carbon ( Molar mass = 12g/mole), 8.80% hydrogen ( Molar mass = 1.01 g/mole) and 15.5% Oxygen (Molar mass = 16.01 g/mole).

Carbon: 75.6g / 12 = 6.29

Hydrogen: 8.80/ 1 = 8.80

Oxygen: 15.5/ 16 = 0.97

⇒0.97 is the smallest so we divide everything through by 0.97

C: 6.29 / 0.97 = 6.48 ≈ 6.5

H: 8.80 /0.97 = 9

O: 0.97 / 0.97 = 1

To get rid of decimals, we multiply by 2

C: 6.5 x 2 = 13

H: 9 x 2 = 18

O: 1 x 2 = 2

The empirical formula = C13H18O2

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The empirical formula = molecular formula = C13H18O2

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Explanation:

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Marina86 [1]

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