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maksim [4K]
3 years ago
11

How do I calculate the molecular weight of Mg(OH)2?

Chemistry
1 answer:
vodomira [7]3 years ago
5 0

The molecular weight of Mg(OH)2 : 58 g/mol

<h3>Further explanation</h3>

Given

Mg(OH)2 compound

Required

The molecular weight

Solution

Relative atomic mass (Ar) of element : the average atomic mass of its isotopes  

Relative molecular weight (M)  : The sum of the relative atomic mass of Ar  

M AxBy = (x.Ar A + y. Ar B)  

So for Mg(OH)2 :

= Ar Mg + 2 x Ar O + 2 x Ar H

= 24 g/mol + 2 x 16 g/mol + 2 x 1 g/mol

= 24 + 32 + 2

= 58 g/mol

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other workers in their company.

Explanation:

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3 years ago
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Vsevolod [243]

Answer:

Explanation:

mass of 1mole of brick =  mass of 1 brick x avagadro number

= 4 kg x 6.022 x 10^23 bricks  = 2.4 x 10^24 kg

No. of moles of bricks have a mass equal to the mass of the earth

= mass of earth / mass of 1 mole of brick

= [ 6 x 10^27 ]  /  [ 2.4 x 10^24 ]

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7 0
3 years ago
Gold is alloyed with other metals to increase its hardness in making jewelery.a) Consider a piece of gold jewelry the weighs 9.8
irinina [24]

Answer:

A). Percentage of gold by mass of the jewellery =

(6.059÷9.85) × 100 = 61.5%

B). Purity of the gold = 0.615 × 24 = 14.76 karat ~ 15 karat gold

Explanation:

Mass of jewellery = 9.85g Volume of jewellery = 0.675cm^3.

Density of gold = 19.3g/cm^3 and density of silver = 10.5g/cm^3

Let the volume of gold in the jewellery be X and the volume of silver in the jewellery be Y

Hence we have

Density = mass/volume or mass = volume × density = for gold = X × 19.3g/cm^3 and for the silver = Y × 10.5g/cm^3

19.3X +10.5Y = 9.85g

Also volume of jewellery is given by

Volume of silver in the jewellery + volume of gold in the jewellery = 0.675cm^3.

X + Y = 0.675cm^3.

Solving the above equations we have

Y = 0.675 - X

Which gives

19.3X + 10.5Y = 9.85g

19.3X + 10.5 × (0.675 - X) =9.85g

19.3X + 7.0875 - 10.5X = 9.85

8.8X + 7.0875 = 9.85

8.8X = 2.7625

or X = 0.3139 cm^3

But Y = 0.675 - X

Hence Y = 0.675 - 0.3139 = 0.3611 cm^3

Mass of gold in the jewellery = volume of gold × Density of gold = 0.3139 × 19.3 = 6.059 g

Also mass of silver = 10.5 × 0.3611 = 3.7913g

A). Percentage of gold by mass of the jewellery =

(6.059÷9.85) × 100 = 61.5%

B). Purity of the gold = 0.615 × 24 = 14.76 karat ~ 15 karat gold

7 0
3 years ago
Calculate the specific heat of a piece of wood if 2000 g of wood absorbs 75,250 J of heat, and its temperature changes from 30°C
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Answer:

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<em>The </em><em>specific</em><em> </em><em>heat </em><em>capacity</em><em>=</em><em>quantity</em><em> of</em><em> </em><em>heat</em><em> </em><em>in </em><em>joule/</em><em>mass×</em><em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>in </em><em>temperature</em>

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<em>which </em><em>is </em><em>2</em><em>0</em>

<em>therefore</em>

<em>c=</em><em>7</em><em>5</em><em>2</em><em>5</em><em>0</em><em>/</em><em>2</em><em>0</em><em>0</em><em>0</em><em>×</em><em>2</em><em>0</em>

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<em>c=</em><em>1</em><em>.</em><em>8</em><em>8</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

3 0
3 years ago
What type of particles move to create electicity?<br> electrons<br> protons<br> neutrons
sladkih [1.3K]

the answer is electrons.....

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3 years ago
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