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3 years ago

What conclusion does the student most likely make based

Physics

2 answers:

inna [77]3 years ago

8 0

Answer:

option a

Explanation:

Light is an electromagnetic wave which can travel in vacuum as well as any medium. The speed of light is maximum in vacuum. The electromagnetic wave travels by oscillating electric and magnetic field to the direction of motion of wave.

On the other hand, sound waves are mechanical waves which can only travel in a medium as they can only move forward by oscillating material particles.

Thus, the student should conclude option a.

cestrela7 [59]3 years ago

4 0

Answer:

Its D: Tightly packed particles in solids slow down the light waves; however, sound waves make particles bounce into each other, so they travel faster in solids.

Explanation:

Got it right on edge

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A cat dozes on a stationary merry-go-round, at a radius of 5.5 m from the center of the ride. Then the operator turns on the rid

bixtya [17]

Answer:

$u_{s}=0.56$

Explanation:

For the cat to stay in place on the merry go round without sliding the magnitude of maximum static friction must be equal to magnitude of centripetal force

$F_{s.max}=\frac{mv^2}{r} \\$

Where the r is the radius of merry-go-round and v is the tangential speed

but

$F_{s.max}=u_{s}F_{N}=u_{s}mg$

So we have

$u_{s}mg=\frac{mv^2}{r}\\ u_{s}=\frac{v^2}{gr}\\ Where\\v=\frac{2\pi R}{T} \\So\\u_{s}=\frac{(\frac{2\pi R}{T} )^2}{gr} \\u_{s}=\frac{4\pi^2 r}{gT^2}$

Substitute the given values

$u_{s}=\frac{4\pi^2 5.5m}{(9.8m/s^2)(6.3s)^2} \\u_{s}=0.56$

6 0

3 years ago

What are the two ost important processes in the oxygen in and out of the atmospher

BaLLatris [955]

Decomposing - When plants and animals die, they decompose. This process uses up oxygen and releases carbon dioxide. Rusting - This is also called oxidation. When things rust they use up oxygen.
$hope \: i \: helped \\ \\ \\ \\ \\ \\ darklynx$

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3 years ago

Read 2 more answers

Consider two identical insulated metal spheres, A and B. Sphere A initially has a charge of -6.0 units and sphere B initially ha

Oksi-84 [34.3K]

Answer:

<em>-2 units of charge</em>

Explanation:

charge on A = Qa = -6 units

charge on B = Qb = 2 units

if the spheres are brought in contact with each other, the resultant charge will be evenly distributed on the spheres when they are finally separated.

charge on each sphere will be = $\frac{Qa + Qb}{2}$