Position: x = 18t y = 4t - 4.9t²
First derivative: x' = 18 y' = 4 - 9.8t
Second derivative: x'' = 0 y'' = - 9.8
Position vector: P = (18t) i + (4t - 4.9t²) j
Velocity vector: V = (18) i + (4 - 9.8t) j
Acceleration vector A = (- 9.8) j
Responder:
20.3 ° C
Explicación:
<u>Según la ley de Charles</u>: <em>cuando la presión sobre una muestra de gas seco se mantiene constante, la temperatura y el volumen estarán en proporción directa.
</em>
Paso uno:
datos dados
Temperatura T1 = 20 ° C
Temperatura T2 =?
Volumen V1 = 12.2 cm ^ 3
Volumen V2 = 12.4 cm ^ 3
Aplicar la relación temperatura y volumen

sustituyendo tenemos

Cruz multiplicar tenemos

Temperatura delle braci 20.3°C
The angle between 2 o'clock and 12 o'clock is referred to as the angle of twist. The angle between the planes of maximum shear which is bisected by the axis of greatest compression is angle of shear.
Answer:
The range of powers is 
Explanation:
From the question we are told that
The far point of the left eye is 
The near point of the left eye is 
The near point with the glasses on is 
From these parameter we can see that with the glass on that for near point the
Object distance would be 
Image distance would be 
To obtain the focal length we would apply the lens formula which is mathematically represented as

substituting values


converting to meters


Generally the power of the lens is mathematically represented as

Substituting values


From these parameter we can see that with the glass on that for far point the
Object distance would be 
Image distance would be 
To obtain the focal length of the lens we would apply the lens formula which is mathematically represented as

substituting values


converting to meters

Generally the power of the lens is mathematically represented as

Substituting values


This implies that the range of powers of the lens in his glass is
