A compound with the formula C6H12 is not considered a Saturated hydrocarbon.
Why is C6H12 isn't considered a Saturated hydrocarbon?
The ring's presence demonstrates that it is unsaturated. Keep in mind that the general formula for aliphatic hydrocarbons, CnH2n+2, serves as the foundation for its saturation. A chemical is unsaturated if it does not meet this requirement.
Example:
Hexane (C6H14)
C = 6; H = 14 = 2(6) + 2
resulting in hexane becoming saturated.
Cyclohexane(C6H12)
C = 6 and H = 12 do not equal 14 (x)!
cyclohexane is an unsaturated molecule as a result.
Cycloalkanes have the general formula C2H2n as well.
Hence, the given statement is false.
Learn more about the hydrocarbons here,
brainly.com/question/17578846
# SPJ4
A- law of conservation of energy
Answer:
1. The electronic configuration of X is: 1s2 2s2 sp6 3s2
2. The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6
3. The formula of the compound form by X and Y is given as: XY
Explanation:
For X to loss two electrons, it means X is a group 2 element. X can be any element in group 2. The electronic configuration of X is:
1s2 2s2 sp6 3s2
To get the electronic configuration of the anion of element Y, let us find the configuration of element Y. This is done as follows:
Y receives two electrons from X to complete its octet. Therefore Y is a group 6 element. The electronic configuration of Y is given below
1s2 2s2 2p4
The configuration of the anion of Y (i.e Y^2-) is 1s2 2s2 2p6
The formula of the compound form by X and Y is given below :
X^2+ + Y^2- —> XY
Their valency will cancel out thus forming XY
Answer:
1335.12 mL of H2O
Explanation:
To calculate the mililiters of water that the solution needs, it is necessary to know that the volume of the solution is equal to the volume of the solute (NaOH) plus the volume of the solvent (H2O).
From the molarity formula we can first calculate the volume of the solution:
![M=\frac{solute moles}{solution volume}](https://tex.z-dn.net/?f=M%3D%5Cfrac%7Bsolute%20moles%7D%7Bsolution%20volume%7D)
![Solutionvolume=\frac{solute moles}{M} =\frac{5mol}{3.5\frac{mol}{L} } =1.429L](https://tex.z-dn.net/?f=Solutionvolume%3D%5Cfrac%7Bsolute%20moles%7D%7BM%7D%20%3D%5Cfrac%7B5mol%7D%7B3.5%5Cfrac%7Bmol%7D%7BL%7D%20%7D%20%3D1.429L)
The volume of the solution as we said previously is:
Solution volume = solute volume + solvent volume
To determine the volume of the solute we first obtain the grams of NaOH through the molecular weight formula:
![MW=\frac{mass}{mol}](https://tex.z-dn.net/?f=MW%3D%5Cfrac%7Bmass%7D%7Bmol%7D)
![Mass=MW*mol=39.997\frac{g}{mol} *5mol=199.985g](https://tex.z-dn.net/?f=Mass%3DMW%2Amol%3D39.997%5Cfrac%7Bg%7D%7Bmol%7D%20%2A5mol%3D199.985g)
Now with the density of NaOH the milliliters of solute can be determined:
![d=\frac{mass}{volume}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7Bmass%7D%7Bvolume%7D)
![Volume=\frac{mass}{d} =\frac{199.985g}{2.13\frac{g}{mL} } =93.88mL of NaOH](https://tex.z-dn.net/?f=Volume%3D%5Cfrac%7Bmass%7D%7Bd%7D%20%3D%5Cfrac%7B199.985g%7D%7B2.13%5Cfrac%7Bg%7D%7BmL%7D%20%7D%20%3D93.88mL%20of%20NaOH)
Having the volume of the solution and the volume of the solute, the volume of the solvent H2O can be calculated:
Solvent volume = solution volume - solute volume
Solvent volume = 1429 mL - 93.88 mL = 1335.12 mL of H2O
It’s one... electron affinity