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ludmilkaskok [199]
3 years ago
13

What is the energy content in joules of a 1.28g sample of oatmeal that raises the temperature of 1.50 kg of water in a calorimet

er from 25.0 C to 27 C
Chemistry
1 answer:
krok68 [10]3 years ago
8 0

Answer:

12560 J.

Explanation:

  • To calculate the energy, we use the relation:

<em>The amount of heat absorbed by water = Q = m.c.ΔT.</em>

where, m is the mass of water (m = 1.5 kg = 1500.0 g).

c is the specific heat capacity of water = 4.186 J/g°C.

ΔT is the temperature difference = (final T - initial T = 27°C - 25°C = 2°C).

∴<em> The amount of heat absorbed by water = Q = m.c.ΔT</em> = (1500.0 g)(4.186 J/g°C)(2°C) = <em>12560 J.</em>

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On the accompanying structural formula,<br> circle the acid functional group, only.
melisa1 [442]

The -COOH attached to the CH3 is the acid functional group.

<h3>What is a functional group?</h3>

The term functional group refers to the atom, group of atoms or bond which accounts for the chemical reactivity of a compound.

The acid functional group is known by the formula -COOH. In this case, we can see that the -COOH attached to the CH3 is the acid functional group.

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3 0
2 years ago
Molecular weight of PbCl2 = 278 g/mole Mass of beaker + PbCl2 = 62.19 g Mass of beaker = 57.77 g Mass of PbCl2 per 100 mL = g Mo
levacccp [35]
PbCl2--->Pb2+  +  2Cl-

The  mass   of  PbCl2   is   =mass   of  the  beaker+Pbcl2  minus   mass  of  the  beaker
that  is  62.19-57.77g=  4.42grams

moles  of PbCl2=  4.42g/278g/m0l = 0.0159moles

concentration  of  (Pb2+)
since  mole  ratio  of  PbCl2  to  Pb2+  is   1:1  therefore  the  moles  of  Pb2+  is  also  0.0159moles
concentration  =0.0159/100 x1000=0.159M

concentration  of  CI-  is  two  time  that  of  Pb2+  from  the  equation  above  therefore  concentration   of  Cl-  =  0.159 x2  =0.318M
7 0
3 years ago
HClO3 + NH3 Right arrow. NH4+ + ClO3– Which is a base-conjugate acid pair?
romanna [79]

Answer:

NH3 and NH4+

Explanation:

5 0
3 years ago
Convert this temperature from °F to °C. Explain how pls?
Tamiku [17]

Answer:

Start with the temperature in Fahrenheit (e.g., 100 degrees).

Subtract 30 from this figure (e.g., 100 - 30 = 70).

Divide your answer by 2 (e.g., 70 / 2 = 35).

7 0
3 years ago
If the volume of the original sample in Part A ( P1 = 242 torr , V1 = 27.0 L ) changes to 80.0 L , without a change in the tempe
Brrunno [24]

The new pressure is 81.675 torr

Since temperature and moles are held constant, we use Boyle's Law:

A gas law known as Boyle's law asserts that a gas's pressure is inversely proportional to its volume when it is held at a fixed temperature and of a given mass.

To put it another way, as long as the temperature and volume of the gas remain constant, the pressure and volume of the gas are inversely proportional to one another.

The Anglo-Irish chemist Robert Boyle proposed Boyle's law in the year 1662.

P1V1=P2V2. Simply plug in your values. The units can remain in torr. Converting to atmospheres is not needed.

(242 torr)(27.0 L)=P2(80.0 L)

P2=[(242)(27)]/80 = 81.675 torr

Hence The new pressure is 81.675 torr

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3 0
2 years ago
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