Answer:
4. A concentration of a trace mineral was found to be 2.53 ppb in an aqueous solution. A. What mass of solution contains 2.53 g of the mineral? (1 point - Knowledge, 2 points - Inquiry, 1 point - Communication) m=? C = 2.53 ppm or 2.53X106 n = Con ܗ B. What volume of solution contains 2.53 g of the mineral? (1 point - Knowledge, 2 points - Inquiry, 1 point - Communication) VE? C: 2,53 ppm ns Cen
The answer will be a or d im not really sure but the two of them will work
Answer:
nahhhhhhhhhhhhhhhhhhhhhhh xD
have a good day :)
Explanation:
(9.44•10^24)(32 g CH3OH) / (6.02•10^23)
501.8 g
