I believe the answer is C.
Based on the given situation, if x is number of kilograms of lobster, you can write the following expressions:
51 + 5x cost in the first restaurant
33 + 8x cost in the second restaurant
In order to determine the value of x which makes the cost the same in both restaurants, equal the previous expressions and solve for x:
51 + 5x = 33 + 8x subtract 33 both sides and 5x subtract both sides
51 - 33 = 8x - 5x simplify
18 = 3x divide by 3 both sides
18/3 = x
6 = x
x = 6
Hence, the weight of the lobster is 6 kg.
The cost of the dinner is:
51 + 5(6) = 51 + 30 = 81
Hence, the cost of the dinner is $81
Answer:
number of $20 bill = 4
Number of $5 bill = 5
Step-by-step explanation:
Given that:
Total number of $5 and $20 bills = 9
Let :
Number of $5 bills = x
Number of $20 bills = y
Combined worth of all bills = $105
x + y = 9 - - - (1)
5x + 20y = 105 - - - (2)
From (1)
x = 9 - y
Substitute x = 9 - y into (2)
5(9 - y) + 20y = 105
45 - 5y + 20y = 105
15y = 105 - 45
15y = 60
y = 60/15
y = 4
x = 9 - y
x = 9 - 4 = 5
Hence,
number of $20 bill = 4
Number of $5 bill = 5
Due to "order of operations" rules, you MUST do the multiplication -5(12x+8) first, eliminating the parentheses long the way:
8 - 60x - 40
Now combine the 8 and -40 and rewrite the entire answer in 2 (not 3) terms.
Answer:
Step-by-step explanation:
It can be between 90° and 180°