All categories

3 years ago

Massive stars have lower absolute brightness true or false

Chemistry

2 answers:

Juliette [100K]3 years ago

6 0

<span>The answer should be false, because mass should not have to do with how bright a star is </span>

Inessa [10]3 years ago

6 0

The brightness of a star is measured as luminosity. It is a simple factor of energy emitted by a star in a unit time or generally per second.

the following factors may affect the brightness of a star

a) Temperature of star

b) size of star: larger the size more the brightness

c) distance from observer : closer the star brighter it will appear

so massive stars or stars with large mass have lower absolute brightness will be false.

You might be interested in

suppose that an ionic compound m represents a metal that could form more than one type of ion. in the formula MO the charge of t

blsea [12.9K]

Answer:

Explanation:

7 0

3 years ago

HELP ME PLEASE WILL MAKE AS BRAINLIES

vredina [299]

1. a 2.b 3 a 4. c. 4.a 5. d 6.a. 2Na + Cl2 2NaC 7.c. 3 8.3 9.b

7 0

3 years ago

Determine the change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizi

uysha [10]

Answer: The change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizing compound is dissolved in it is $2.9^0C$

Explanation:

Elevation in boiling point:

$T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of pure carbon disulfide= $46.2^oC$

$k_b$ = boiling point constant = $2.34^0Ckg/mol$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute = 35.0 g

$w_1$ = mass of solvent (carbon disulphide) = 397.7 g

$M_2$ = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

$(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}$

$T_b=49.1^0C$

Therefore, the change in boiling point is $(49.1-46.2)^oC=2.9^0C$

5 0

3 years ago

Explain the term respiration and how this process increases the percentage of carbon dioxide in the atmosphere.

sammy [17]

Answer:

Please find the explanation to this question below.

Explanation:

4 0

3 years ago

Calculate the amount of ATP in kg that is turned over by a resting human every 24 hours. Assume that a typical human contains ~5

valentinak56 [21]

Answer:

The correct answer is 66.35 kilograms.

Explanation:

Based on the data given in the question, the energy consumed by the body of a human being is 50%. Based on the given data, the energy consumed in a day is 8000 kJ, 50 percent is the energy transfer efficiency. Thus, the consumption of total energy is 4000 kJ, and for the transformation of ADP to ATP, the energy involved is 30.6 kJ per mole.

Hence, the total ATP produced in the process is,

ATP = 4000 kJ / 30.6 kJ/mol

= 130.7189 mol.

Thus, with the energy transfer efficiency of 50 percent, the total moles of ATP produced is 130.7 mol.

The mass of ATP can be calculated by using the formula,

moles = mass/molecular mass

The molecular mass of ATP is 507.18 g per mol

Now by putting the values we get,

mass of ATP = 130.7189 mol * 507.18 g/mol

= 66298.011 g or 66.298 kg

It is mentioned that human comprise 50 g of ATP or 0.05 kg of ATP. Therefore, the sum of the available ATP will be.

= Total production of ATP + Total ATP available

= 66.298 kg + 0.05 kg

= 66.348 kg

Hence, the sum of the ATP that is turned over by a resting human in a day is 66.35 kg.

5 0

3 years ago