Answer:
Work done in all the three cases will be the same.
Explanation:
1) The free falling body has only one force acting on it, the gravitational force. The work done on the body = mgH (Gravitational potential energy)
2) There are two forces acting on the body going down on a frictionless inclined plane - gravity and the normal force. The gravitational potential energy will be the same. The work done due to the normal force is zero, since the direction of the force is perpendicular to the displacement. Hence, total work done on the body = mgH
3) In the case of the body swinging on the end of a string, the change in gravitational potential enrgy will once again be the same since difference in height is H. The additional force on the body is the tension due to the string. But the work done due to this force is <em>zero, </em>since the displacement of the body is perpendicular to the tension. Therefore, the total work done on the body is once again mgH.
Answer:
1/f = 1/o + 1 /i thin lens equation
1 / i = 1/f - 1/o = (o - f) / (o f) rearranging
or i = o f / (o - f) for the image distance
This image will be positive (real) with values given
m = -i / o magnification
m = - f / (o - f) shows m is negative and the image inverted
Also, since o here is large m will be small and the image is small
I think they mean A as the right answer
Different texts use different terms but here i is image distance and o the object distance
<u>Answer</u>
3.7 Km south
<u>Explanation</u>
The definition of displacement is the distance traveled in a specific direction. It is the vector quantity. We add displacements like the way we add vectors.
Taking the direction towards North to be positive (+1.7 Km), the distance towards south would be negative (-5.4 Km).
Now lets add the two values.
(+1.7) + (-5.4) = 1.7 - 5.4
= - 3.7 Km But negative was towards south.
∴ Answer = 3.7 Km south.
Answer: A) 7.5v
B) 75000v/m
C) 1.66×10^-11
D) 7.5v
E) 232500v/m
F) 5.15×10^-11
Explanation:
The potential difference will be the same for the two cases.
Please find the attached file for the solution
