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Rom4ik [11]3 years ago

6 0

The car will gain new momentum if it's velocity is doubled or tripled.

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TheE-field strength is 50,000 N/C inside a parallel plate capacitor with 2.0 mmspacing. A proton is released from rest at the po

Ghella [55]

Answer:

The speed is $138852.4 \frac{m}{s}$

Explanation:

Electric field magnitude (E) and electric force magnitude (F) are related by the equation

$F=Eq$

with q the charge of the proton ( $1.61\times10^{-19} C$ ). Because between parallel plates electric field is almost constant, electric force is constant too:

$F=(50000)(1.61\times10^{-19})=8.05\times10^{-15}N$

because electric force is constant, then by Newton's second law acceleration (a) is constant too, it is:

$a=\frac{F}{m}$

with m the mass of the proton ( $1.67\times10^{-27} kg$ ):

$a=\frac{8.05\times10^{-15}}{1.67\times10^{-27}}= 4.82\times10^{12}\frac{m}{s^{2}}$

Now with this constant acceleration we can use the kinematic equation

$v^{2}=v_{0}^{2}+2ad$

with v the final speed, $v_i$ the initial velocity that is zero (because proton starts at rest) and d is the distance between the plates, so:

$v=\sqrt{2ad}=\sqrt{2(4.82\times10^{12}\frac{m}{s^{2}})(2.0\times10^{-3}m)}$

$v=138852.4 \frac{m}{s}$

5 0

3 years ago

(a) calculate the speed of a proton after it accelerates from rest through a potential difference of 215 v. m/s (b) calculate th

bija089 [108]

<span>The proton differs from the electron in sign although they have the same value. Like the electron, a proton will gain 215 electron-volts of eV in Kinetic energy. So 1.602Ă—10^-19 J * 215 = 344.43 * 10^(-19) J. But K. E. = mv^2 / 2, so v^2 = 2 * K.E/m. The mass of a proton is 1.673 * 10^-27 kg. So v = âš(2 * 344.43 * 10^(-19))/1.673Ă—10^-27 = 688.86 * 10^(-19)/1.673Ă—10^(-27) = 411.75 * 10^(-19-(-27)) = âš411.75 * 10^(8) = 202196.56 Also for the electron we have v^2 = 2 * K.E/m but here mass, m, = 9.109 * 10^-31 kg. So we have v = âš(2 * 344.43 * 10^(-19)) / 9.109 * 10^-31 = 688.86 * 10^(-19)/ 9.109 * 10^-31 = 75.624 * 10^(-19 - (-31)) = 75.624 * 10^(21) and v = 2.749 * 10^11</span>

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3 years ago

Small pockets of synovial fluid that reduce friction and act as a shock absorber where ligaments and tendons rub against other t

Aloiza [94]

Answer:

bursae.

Explanation:

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3 years ago

A boy is pedaling his bicycle at a velocity of 0.20km/ minute . How far will he travel in 2.5 hours

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30km. 24 the first two hours and 6 the half hour