1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mrs_skeptik [129]
3 years ago
11

I need help with...

Physics
1 answer:
Rom4ik [11]3 years ago
6 0
The car will gain new momentum if it's velocity is doubled or tripled.
You might be interested in
TheE-field strength is 50,000 N/C inside a parallel plate capacitor with 2.0 mmspacing. A proton is released from rest at the po
Ghella [55]

Answer:

The speed is 138852.4 \frac{m}{s}

Explanation:

Electric field magnitude (E) and electric force magnitude (F) are related by the equation

F=Eq

with q the charge of the proton (1.61\times10^{-19} C). Because between parallel plates electric field is almost constant, electric force is constant too:

F=(50000)(1.61\times10^{-19})=8.05\times10^{-15}N

because electric force is constant, then by Newton's second law acceleration (a) is constant too, it is:

a=\frac{F}{m}

with m the mass of the proton (1.67\times10^{-27} kg):

a=\frac{8.05\times10^{-15}}{1.67\times10^{-27}}= 4.82\times10^{12}\frac{m}{s^{2}}

Now with this constant acceleration we can use the kinematic equation

v^{2}=v_{0}^{2}+2ad

with v the final speed, v_i the initial velocity that is zero (because proton starts at rest) and d is the distance between the plates, so:

v=\sqrt{2ad}=\sqrt{2(4.82\times10^{12}\frac{m}{s^{2}})(2.0\times10^{-3}m)}

v=138852.4 \frac{m}{s}

5 0
3 years ago
(a) calculate the speed of a proton after it accelerates from rest through a potential difference of 215 v. m/s (b) calculate th
bija089 [108]
<span>The proton differs from the electron in sign although they have the same value. Like the electron, a proton will gain 215 electron-volts of eV in Kinetic energy. So 1.602Ă—10^-19 J * 215 = 344.43 * 10^(-19) J. But K. E. = mv^2 / 2, so v^2 = 2 * K.E/m. The mass of a proton is 1.673 * 10^-27 kg. So v = âš(2 * 344.43 * 10^(-19))/1.673Ă—10^-27 = 688.86 * 10^(-19)/1.673Ă—10^(-27) = 411.75 * 10^(-19-(-27)) = âš411.75 * 10^(8) = 202196.56 Also for the electron we have v^2 = 2 * K.E/m but here mass, m, = 9.109 * 10^-31 kg. So we have v = âš(2 * 344.43 * 10^(-19)) / 9.109 * 10^-31 = 688.86 * 10^(-19)/ 9.109 * 10^-31 = 75.624 * 10^(-19 - (-31)) = 75.624 * 10^(21) and v = 2.749 * 10^11</span>
3 0
3 years ago
Small pockets of synovial fluid that reduce friction and act as a shock absorber where ligaments and tendons rub against other t
Aloiza [94]

Answer:

bursae.

Explanation:

7 0
3 years ago
A boy is pedaling his bicycle at a velocity of 0.20km/ minute . How far will he travel in 2.5 hours
fredd [130]
30km. 24 the first two hours and 6 the half hour
4 0
3 years ago
Read 2 more answers
In the mixtures lab, you waited to see if the liquid would form lumpy or fluffy masses, which would indicate it was a _____.
Over [174]
B) colloid because i took the test and that the answer

5 0
3 years ago
Read 2 more answers
Other questions:
  • A block with mass m = 4.5 kg is attached to two springs with spring constants kleft = 36 N/m and kright = 50 N/m. The block is p
    14·1 answer
  • During a fission each time an atom divides ___.
    5·2 answers
  • An object of mass 10kg is accelerated upward at 2m/s^2. What force is required
    7·1 answer
  • A toy rocket moving vertically upward passes by a 2.0-m-high window whose sill is 8.0 m above the ground. The rocket takes 0.15
    9·1 answer
  • Unpolarized light of intensity I0 is incident on two polarizing filters. The transmitted light intensity is I0/10. What is the a
    5·1 answer
  • Three small spheres, having masses m1 = 1 kg, m2 = 3 kg, and m3 = 4 kg, are held fixed on the x axis in deep space where the eff
    13·2 answers
  • What are the two <br>factors in which weight of object depends?​
    9·2 answers
  • Matter is defined as anything that has weight and takes up space.
    8·1 answer
  • P = Patm + pgh is which law
    5·1 answer
  • A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 12000 kg heading north at 30 m/s. When the cars
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!