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Vera_Pavlovna [14]
3 years ago
10

The manipulation of natural sounds via the medium of magnetic tape is called

Physics
1 answer:
alexandr1967 [171]3 years ago
3 0
<span>The manipulation of natural sounds via the medium of magnetic tape is called "</span>Musique concrete".

Musique concrete refers to an experimental method of melodic composition utilizing recorded sounds as crude material. The strategy was created around 1948 by the French composer Pierre Schaeffer and his partners at the Studio d'Essai ("Experimental Studio") of the French radio framework. The major guideline of musique concrète lies in the collection of different regular sounds recorded on tape (or, initially, on plates) to deliver a montage of sound.
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A car travels West at 35 mph for a time period of 2.5 hours and then travels West at 55 mph for an additional time of 4.0 hours.
OlgaM077 [116]

The total distance travelled is 307.5 miles.

<h3>What is the distance covered?</h3>

We know that the distance covered can be obtained from the formula from speed since the motion all took place in the same direction.

Speed = distance/time

distance = speed * time

In the first case;

Distance =  35 mph  *  2.5 hours = 87.5 miles

In the second case;

Distance =  55 mph * 4.0 hours = 220 miles

Total distance = 87.5 miles + 220 miles = 307.5 miles

Hence the total distance travelled is 307.5 miles.

Learn more about total distance:brainly.com/question/20330990

#SPJ1

7 0
2 years ago
Two charged spheres are 8.45 cm apart. They are moved, and the force on each of them is found to have been tripled. How far apar
Aleonysh [2.5K]

Force between two charges is given by

F = \frac{kq_1q_2}{r^2}

here force is inversely depends on the square of the distance

so here if distance is decreased the force will increase'

now if force is tripled

\frac{3F}{F} = \frac{r^2}{r'^2}

initially distance between charges was 8.45 cm

3 = \frac{8.45^2}{r'^2}

r' = \frac{8.45}{\sqrt3}

r' = 4.88 cm

so the distance between charges is 4.88 cm now

4 0
3 years ago
What is the weight of the body under the influence of a force of 10N reaches a speed of 1.5 m / s in 3s?
MariettaO [177]

Answer:

Explanation:

F=ma

F=10N

A=v-u upon t

=1.5-0 upon 3

=0.5m per second squared

Then do force divided by. Accelaration and multiply by gravity.

8 0
2 years ago
Referring to the graph below of data describing a cart pulled across a level surface. When a 4 N force pulls on the cart, the ca
LenKa [72]

Answer:gjv

Explanation:

4 0
2 years ago
Read 2 more answers
1.Convert 340 cm into m *(answer=0.34m)
Nataly [62]

Answer:

<em>1</em><em>.</em><em>for </em><em>the </em><em>first </em><em>one </em><em>100c</em><em>e</em><em>n</em><em>t</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em>s</em><em> </em><em>make </em><em>1</em><em> </em><em>meter </em><em>therefore</em>

<em>100c</em><em>m</em><em>-</em><em>1</em><em>m</em>

<em>3</em><em>4</em><em>0</em><em>c</em><em>m</em><em>-</em><em>x</em>

<em>3</em><em>4</em><em>0</em><em>/</em><em>100</em>

<em>=</em><em>3</em><em>.</em><em>4</em>

<em>the </em><em>answer </em><em>is </em><em>supposed</em><em> to</em><em> be</em><em> </em><em>3</em><em>.</em><em>4</em><em>,</em><em> maybe</em><em> </em><em>there's</em><em> </em><em>a </em><em>mistake</em><em> </em><em>with </em><em>the </em><em>question</em><em> </em><em>or </em><em>the </em><em>answer</em>

<em>2</em><em>.</em><em>t</em><em>h</em><em>e</em><em> </em><em>weight</em><em> </em><em>of </em><em>a </em><em>body </em><em>is </em><em>given </em><em>by </em><em>the </em><em>formula</em>

<em>mass×</em><em>g</em><em>r</em><em>a</em><em>v</em><em>i</em><em>t</em><em>y</em><em>,</em><em>in </em><em>this </em><em>case </em><em>the </em><em>mass </em><em>is </em><em>7</em><em>5</em><em>k</em><em>g</em><em> </em><em>and </em><em>the </em><em>gravity </em><em>is </em><em>9</em><em>.</em><em>8</em>

<em>weight</em><em>=</em><em>7</em><em>5</em><em>×</em><em>9</em><em>.</em><em>8</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>7</em><em>3</em><em>5</em><em>N</em>

<em>3</em><em>.</em><em>f</em><em>o</em><em>r</em><em> </em><em>this </em><em>one </em><em>the </em><em>mass </em><em>of </em><em>a </em><em>body </em><em>is </em><em>given</em><em> by</em><em> the</em><em> formula</em>

<em>mass=</em><em>weight/</em><em>gravity</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>4</em><em>2</em><em>0</em><em>/</em><em>9</em><em>.</em><em>8</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>4</em><em>2</em><em>.</em><em>8</em><em>k</em><em>g</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

4 0
3 years ago
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