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12345 [234]
4 years ago
15

Give the number of significant figures: 0.01101 cm

Chemistry
1 answer:
Delvig [45]4 years ago
6 0

Answer: 4

Explanation:

All nonzero digits are significant as well as zeros in between nonzero figures, but preceding zeros are not significant.

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58.0 g of K2SO4 was dissolved in 500 g of water. What is the molality of this solution?
podryga [215]

Answer: The molality of solution is 0.66 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n\times 1000}{W_s}

where,

n = moles of solute

W_s = weight of solvent in g

moles of K_2SO_4 = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{58.0g}{174g/mol}=0.33mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.33\times 1000}{500g}=0.66mole/kg

Therefore, the molality of solution is 0.66 mole/kg

7 0
3 years ago
Convert 6.33×10−6 cg to nanograms.
tensa zangetsu [6.8K]
5.73e+8 hope this help
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3 years ago
Consider an amphoteric hydroxide, M ( OH ) 2 ( s ) , where M is a generic metal. M ( OH ) 2 ( s ) − ⇀ ↽ − M 2 + ( aq ) + 2 OH −
kvv77 [185]

Answer:

1(374€×737€÷63718477284™>)2638185837+2737=12837

8 0
4 years ago
A line graph that plots distance against _____ shows the motion of an object. speed time velocity direction
Anit [1.1K]
A line graph that plots distance against time shows the motion of an object
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4 years ago
The following mechanism has been proposed for the conversion of tert-butyl bromide to tert-butyl alcohol in aqueous solution: st
Gelneren [198K]

Answer:

See explanation

Explanation:

The first step in this reaction is a unimolecular reaction. It involves the formation of the carbocation. This is so because tertiary alkyl halides only undergo substitution by SN1 mechanism due to sterric crowding.

The second step in the reaction is bi molecular. In this step, the carbocation now combines with the OH^- to yield the alcohol.

Net equation of the reaction is;

(CH3)3CBr + OH^- -------> (CH3)3COH + Br^-

The intermediate here is the carbocation,  (CH3)3C^+

8 0
3 years ago
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