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3 years ago

5

Gamma ray bursters are objects in the universe that emit pulses _________

2 answers:

Natali [406]3 years ago

7 0

Answer:

<em>Gamma rays with high energies</em>

<em>Explanation:</em>

<em>The frequency of t most energetic bursts has been estimated at about</em>

<em>3.0 × 1021 Hz. The light speed estimated to be is 3 × 108 m/s</em>

<em>R=Then the wavelength of the gamma rays is</em>

<em>c = 3.00 x 10^8 m/s </em>

<em>f = 3.0 x 10^21 Hz </em>

<em> λ = c/f </em>

<em>λ = 3.00 x 10^8 / 3.0 x 10^21 </em>

<em>λ = 3.0 x 10^-13 nm</em>

Masteriza [31]3 years ago

6 0

Answer: of gamma rays with high energies.

Explanation:Gamma-ray bursts are extremely energetic explosions that have been observed in distant galaxies. They are the brightest electromagnetic events known to occur in the universe.

The frequency of the most energetic bursts has been measured at around 3.0×1021 3.0 × 10 21 Hz.

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Sorry I’ve just been having trouble with this question

tiny-mole [99]

Answer:

68.8 N 13.8°N of W

Explanation:

F₁ is 50 N 30°N of W. The terminal angle is 150°.

F₂ is 25 N 20°S of W. The terminal angle is -160°.

Graphically, you can add the vectors using head-to-tail method. Move F₂ so that the tail of the vector is at the head of F₁. The resultant vector will be from the tail of F₁ to the head of F₂.

Algebraically, find the x and y components of each vector.

F₁ₓ = 50 N cos(150°) = -43.3 N

F₁ᵧ = 50 N sin(150°) = 25 N

F₂ₓ = 25 N cos(-160°) = -23.5 N

F₂ᵧ = 25 N sin(-160°) = -8.6 N

The x and y components of the resultant vector are the sums:

Fₓ = -43.3 N + -23.5 N = -66.8 N

Fᵧ = 25 N + -8.6 N = 16.4 N

The magnitude of the resultant force is:

F = √(Fₓ² + Fᵧ²)

F = √((-66.8 N)² + (16.4 N)²)

F = 68.8 N

The direction of the resultant force is:

θ = tan⁻¹(Fᵧ / Fₓ)

θ = tan⁻¹(16.4 N / -66.8 N)

θ = 166.2°

θ = 13.8°N of W

6 0

3 years ago

What is the acceleration of a 25 kg object when a 200 N force is applied to it?

Sav [38]

Answer: 8

Explanation: 200/25=8

5 0

3 years ago

!!! HELP PLEASE !!!

maksim [4K]

Answer:

A. you would want to use the 12 ound ball and the 18 mph speed in order to transfer the most kinetic energy

B. KE= 1/2 MV^2 so you would want to maximize both your Mass(weight of the ball) and Velocity(speed of the roll) in order to achive the greatest KE.

C. see image

Explanation:

Full disclosure not totally sure what you are being asked in the last one but I put togethere a rough sketch that is my best guess.

3 0

3 years ago

At highway speeds, a particular automobile is capable of an acceleration of about 2.0 m/s2 . Part A At this rate, how long does

Natasha_Volkova [10]

Answer:

Time taken, t = 4.86 seconds

Explanation:

Given that,

Acceleration of a particular automobile, $a=2\ m/s^2$

Initial speed of the automobile, u = 75 km/h = 20.83 m/s

Final speed of the automobile, v = 110 km/h = 30.55 m/s

We need to find the time taken to accelerate from u to v. Let t is the time taken. It can be calculate as :

$t=\dfrac{v-u}{a}$

$t=\dfrac{30.55-20.83}{2}$

t = 4.86 seconds

So, the time taken by the automobile is 4.86 seconds. Hence, this is the required solution.

5 0

3 years ago

Read 2 more answers

A uniform rod of mass M and length L is free to swing back and forth by pivoting a distance x from its center. It undergoes harm

Alisiya [41]

Answer:

The moment of inertia is 0.7500 kg-m².

Explanation:

Given that,

Mass = 2.2 kg

Distance = 0.49 m

If the length is 1.1 m

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=\dfrac{1}{12}ml^2+mx^2$

Where, m = mass of rod

l = length of rod

x = distance from its center

Put the value into the formula

$I=\dfrac{1}{12}\times2.2\times(1.1)^2+2.2\times(0.49)^2$

$I=0.7500\ kg-m^2$

Hence, The moment of inertia is 0.7500 kg-m².

5 0

3 years ago