First we need to write down heat capacity for water which is constant.
cp=4186 J/(kg*K)
The equation for Energy that we will be calculating is:
E=cp*m*T
where m is mass and T is absolute temperature (273,15 + 60 in this case). Replacing all the values in equation we get:
E = 4186*100*333,15 = 139 456 590 J
Answer:
..
Explanation:
Coordinate adjectives are adjectives that describe the same noun equally. They should be separated with commas. In this sentence, both red and round are describing the ball. The correct answer is, "The red, round ball is Adley's favorite toy to play with."
Answer:
V₀y = 0 m/s
t = 2.47 s
V₀ₓ = 61.86 m/s
Vₓ = 61.86 m/s
Explanation:
Since, the ball is hit horizontally, there is no vertical component of velocity at initial point. So, the initial vertical velocity (V₀y) will beL
<u>V₀y = 0 m/s</u>
For the initial vertical velocity of golf ball we consider the vertical motion and apply 2nd equation of motion:
Y = V₀y*t + (0.5)gt²
where,
Y = Height = 30 m
g = 9.8 m/s²
t = time to hit the ground = ?
Therefore,
30 m = (0 m/s)(t) + (0.5)(9.8 m/s²)t²
t² = 30 m/4.9 m/s²
t = √6.122 s²
<u>t = 2.47 s</u>
For initial vertical velocity we analyze the horizontal motion of the ball. We neglect the frictional effects in horizontal motion thus the speed remains uniform. Hence,
V₀ₓ = Xt
where,
V₀ₓ = Initial vertical Velocity = ?
X = Horizontal Distance = 25 m
Therefore,
V₀ₓ = (25 m)(2.47 s)
<u>V₀ₓ = 61.86 m/s</u>
<u></u>
Due, to uniform motion in horizontal direction:
Final Vertical Velocity = Vₓ = V₀ₓ
Vₓ = 61.86 m/s
The initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s
<h3>What fraction of the initial mass of the spacecraft?</h3>
Increase the speed: Vf-Vi = 2.2 m/s
Speed of aircraft: Vr = 400 m/s
Speed of ejected products: Vrel = 1000 m/s
The answer is:
So, the initial mass fraction of the spacecraft that must be burned and ejected to achieve an increase in speed is 0,00219 m/s
Learn more about spaceship speed fraction brainly.com/question/28256735
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5.972 × 10^24 kg
it is the weight of earth
hope it is helpful to you
