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Ostrovityanka [42]
4 years ago
15

A volleyball is hit and experiences a net

Physics
1 answer:
Ierofanga [76]4 years ago
6 0

Answer: 0.25 kg

Explanation:

Given that,

net force = 2 N

acceleration of volleyball = 8 m/s

mass of the volleyball = ?

According to the Newton 2nd law of motion, net force depends on the mass of the object and acceleration by which it moves.

i.e Net force = mass x acceleration

2N = mass x 8m/s²

Mass = 2N / 8m/s²

Mass = 0.25 kg

Thus, the mass of the volleyball is 0.25 kg

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jonny [76]
P = mv \\ m =  \frac{P}{v}  \\
3 0
3 years ago
What happens when a vector is multiplied by a scalar?
iogann1982 [59]

The scalar operates only on the magnitude of the vector. 
So the length of the vector may change ... becoming longer
or shorter ... but its direction doesn't change.


3 0
4 years ago
NEED TODAY
lisabon 2012 [21]

Answer:

No, projectile launched at 20° landed first.

Explanation:

70° projectile had a vertical velocity of v*sin(70), which is significantly bigger than v*sin(20). Since v=vx+at, we can see that Vyi*sin(20)-gt < Vyi*sin(70)-gt

solve for t, you can check that by substituting velocity for any number.

3 0
2 years ago
Read 2 more answers
An 888.0 kg elevator is moving downward with a velocity of 0.800 m/s. It decelerates uniformly and comes to a stop in a distance
bagirrra123 [75]

Answer:

The value of tension on the cable T = 1065.6 N

Explanation:

Mass = 888 kg

Initial velocity ( u )= 0.8 \frac{m}{sec}

Final velocity ( V ) = 0

Distance traveled before come to rest = 0.2667 m

Now use third law of motion V^{2} = u^{2} - 2 a s

Put all the values in above formula we get,

⇒ 0 = 0.8^{2} - 2 × a ×0.2667

⇒ a = 1.2 \frac{m}{sec^{2} }

This is the deceleration of the box.

Tension in the cable is given by T = F = m × a

Put all the values in above formula we get,

T = 888 × 1.2

T = 1065.6 N

This is the value of tension on the cable.

5 0
4 years ago
What is the wavelength, in nm, of a photon with energy
lara31 [8.8K]

Answer:

(a)  λ = 4136 nm → infrared

(b) λ = 413.6 nm → visible light

(c) λ = 41.36 nm → ultraviolet

Explanation:

The wavelength of infrared is on the range of 700 nm to 1000000 nm

The wavelength of visible light is between 400 nm and 700 nm

The wavelength of ultraviolet ray on the range of 10 nm to 400 nm

The wavelength of photon is given by;

E = hf

f is the frequency of the wave = c / λ

E = h\frac{c}{\lambda}\\\\ \lambda = \frac{hc}{E}

Where;

c is the speed of light = 3 x 10⁸ m/s

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

(a) 0.3 eV = 0.3 x 1.602 x 10⁻¹⁹ J

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(0.3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-6} \ m

λ = 4136 x 10⁻⁹ m

λ = 4136 nm → infrared

(b) 3.0 eV

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-7} \ m

λ = 413.6 x 10⁻⁹ m

λ = 413.6 nm →visible light

(c) 30 eV

\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(30)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-8} \ m

λ = 41.36 x 10⁻⁹ m

λ = 41.36 nm →ultraviolet

5 0
3 years ago
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