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Ostrovityanka [42]
3 years ago
15

A volleyball is hit and experiences a net

Physics
1 answer:
Ierofanga [76]3 years ago
6 0

Answer: 0.25 kg

Explanation:

Given that,

net force = 2 N

acceleration of volleyball = 8 m/s

mass of the volleyball = ?

According to the Newton 2nd law of motion, net force depends on the mass of the object and acceleration by which it moves.

i.e Net force = mass x acceleration

2N = mass x 8m/s²

Mass = 2N / 8m/s²

Mass = 0.25 kg

Thus, the mass of the volleyball is 0.25 kg

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I think it's a pulley and a lever.
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Help me please and thank you
katovenus [111]

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3 0
3 years ago
You drag a suitcase of mass 8.2 kg with a force of f at an angle 41.9 ◦ with respect to the horizontal along a surface with kine
DedPeter [7]

Answer:

35.6 N

Explanation:

We can consider only the forces acting along the horizontal direction to solve the problem.

There are two forces acting along the horizontal direction:

- The horizontal component of the pushing force, which is given by

F_x = F cos \theta

with \theta=41.9^{\circ}

- The frictional force, whose magnitude is

F_f = \mu mg

where \mu=0.33, m=8.2 kg and g=9.8 m/s^2.

The two forces have opposite directions (because the frictional force is always opposite to the motion), and their resultant must be zero, because the suitcase is moving with constant velocity (which means acceleration equals zero, so according to Newton's second law: F=ma, the net force is zero). So we can write:

F_x - F_f=0\\F_x = F_f\\F cos \theta = \mu mg\\F=\frac{\mu mg}{cos \theta}=\frac{(0.33)(8.2 kg)(9.8 m/s^2)}{cos(41.9^{\circ})}=35.6 N

8 0
3 years ago
Scientist who first proposed the theory that the continents drifted is __________
Aloiza [94]

Answer:

Alfred Wegener

Explanation:

Alfred Wegener is a german meteorologist who proposed the theory that the continents drifted, and he presented it to the German Geological Society on January 1912.

4 0
3 years ago
A block of 250-mm length and 48 × 40-mm cross section is to support a centric compressive load P. The material to be used is a b
Marrrta [24]

Answer:

153.6 kN

Explanation:

The elastic constant k of the block is

k = E * A/l

k = 95*10^9 * 0.048*0.04/0.25 = 729.6 MN/m

0.12% of the original length is:

0.0012 * 0.25 m = 0.0003  m

Hooke's law:

F = x * k

Where x is the change in length

F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)

The compressive load will generate a stress of

σ = F / A

F = σ * A

F = 80*10^6 * 0.048 * 0.04 = 153.6 kN

The smallest admisible load is 153.6 kN

8 0
3 years ago
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