As you were holding the block down and in place, the spring exerted an upward force that balanced the downward push by your hand and its own weight. So this restoring force has a magnitude of <em>R</em> such that
<em>R</em> - 50 N - (3 kg) <em>g</em> = 0 => <em>R</em> = 79.4 N
As soon as you remove your hand, the block has acceleration <em>a</em> such that, by Newton's second law,
<em>R</em> - (3 kg) <em>g</em> = (3 kg) <em>a</em> => <em>a</em> = (79.4 N - (3 kg) <em>g</em>) / (3 kg) ≈ 16.7 m/s^2
pointing upward.
Answer:
a) dB / dA = 2
,
b) Network B Network A
2 1
4 2
6 3
Explanation:
a) The expression for grating diffraction is
d sin θ = m λ
where d the distance between two slits, λ the wavelength and m an integer that represents the diffraction range
In this exercise we are told that the two spectra are in the same position, let's write the expression for each network
Network A
m = 1
sin θ = 1 λ / dA
Network B
m = 2
sin θ = 2 λ / dB
they ask us for the relationship between the distances, we match the equations
λ / dA) = 2 λ / dB
dB / dA = 2
b) let's write the equation of the networks
sin θ = m_A λ / dA
sin θ = m_B λ / dB
we equalize
m_A λ/ dA = m_B λ / dB
we use that
dB / dA = 2
m_A 2 = m_B
therefore the overlapping orders are
Network B Network A
2 1
4 2
6 3
Answer is C: Ability to see three-dimensional images of the surfaces of object
Explanation:
To enable the technician see fractures and broken particles in a better resolution as the SEM sees the peaks and valley of the structure.
Answer:
0.005 V
Explanation:
We are given that
Initial circumference of circular loop=C=165 cm
Rate of circumference,
Magnetic field,B=0.5 T
We have to find the induced emf at time t=9 s
We know that induced amf,E=
Area of circular coil,A=
Circumference of circular coil,C=
Radius of coil at time t=9 s
E=
Magnitude of induced emf=0.005 V
