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goldfiish [28.3K]
3 years ago
9

A dog sees a cat and runs for 10 s at 4.8 m/s before the cat runs up a tree

Physics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

Explanation:

Since the dog is running at uniform velocity , distance can be calculated with the help of following relation .

distance travelled = velocity x time

= 4.8 x 10

= 48 m

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Jack and Jill are on two different floors of their high rise office building and looking out of their respective windows. Jack s
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Answer:

a) speed when Jack sees the pot : 12.92 meters per second

b) height difference 163.115 meters

Explanation:

First to calculate te initial speed we use the acceleration formula:

a= v1-v0/t

Acceleration being gravity's acceleration (9.8 m/s^2)

v1 being the speed when Jill sees the pot

v0 when Jack sees it

and t the time between

Solving for v0 it would be

v1 - a*t = v0

replacing

58 m/s -  9.8 m/s^2 *4.6 s = v0 = 12.92 m/s

For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)

The formula is

y0 + v0*t + 1/2 g *t^2 = yt

replacing

0m + 12.92m/s* 4.6 s + 1/2 * 9.8 m/s^2 * (4.6 s)^2 = 163.115 m

5 0
2 years ago
If 20 beats are produced within one second, which of the following frequencies could possibly be held by two sound waves traveli
NeTakaya

Answer:

D. 22 Hz and 42 Hz

Explanation:

  • When two waves with different frequency travelling in the same medium meet each other, they produce an interference pattern called beat.
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  • <em><u>Therefore; in this case since the frequency of the beat is 20 Hz, that is from 20 beats per second.</u></em>
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  • This happens to be choice D. 22 Hz and 42 Hz,  that is 42 Hz - 22 Hz = 20 Hz
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Explanation:

35 ÷ 5 = 7kg.

=======================

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