(a) The location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.
(b) The magnitude and direction of the electric field at the top corner due to the two charges at the base is 1.732 kq/a².
<h3>
Position where the electric field is zero</h3>
The electric field is zero at the center of the equilateral triangle whose magnitude is equal to √3a/6.
<h3>Electric field at top corner due to two charges at the base</h3>
E = E₁ + E₂
where;
- E₁ is electric field at the left base corner
- E₂ is electric field at the right base corner
E = kq/a²[(cos 60i + sin 60j) + (-cos 60i + sin 60j)]
E = kq/a²[2(sin 60j)] = 1.732 kq/a²
Thus, the location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.
The magnitude and direction of the electric field at the top corner due to the two charges at the base is 1.732 kq/a².
Learn more about electric field here: brainly.com/question/14372859
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