Question

Three equal positive charges 'q' are at the corners of an equilateral triangle of side 'a'.

Answer 1

(a) The location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.

(b) The magnitude and direction of the electric field at the top corner due to the two charges at the base is  1.732 kq/a².

Position where the electric field is zero

The electric field is zero at the center of the equilateral triangle whose magnitude is equal to √3a/6.

Electric field at top corner due to two charges at the base

E = E₁ + E₂

where;

• E₁ is electric field at the left base corner
• E₂ is electric field at the right base corner

E = kq/a²[(cos 60i + sin 60j) + (-cos 60i + sin 60j)]

E = kq/a²[2(sin 60j)] = 1.732 kq/a²

Thus, the location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.

The magnitude and direction of the electric field at the top corner due to the two charges at the base is  1.732 kq/a².

Learn more about electric field here: brainly.com/question/14372859

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