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Paha777 [63]
2 years ago
7

Three equal positive charges 'q' are at the corners of an equilateral triangle of side 'a'.

Physics
1 answer:
NARA [144]2 years ago
5 0

(a) The location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.

(b) The magnitude and direction of the electric field at the top corner due to the two charges at the base is  1.732 kq/a².

<h3>Position where the electric field is zero</h3>

The electric field is zero at the center of the equilateral triangle whose magnitude is equal to √3a/6.

<h3>Electric field at top corner due to two charges at the base</h3>

E = E₁ + E₂

where;

  • E₁ is electric field at the left base corner
  • E₂ is electric field at the right base corner

E = kq/a²[(cos 60i + sin 60j) + (-cos 60i + sin 60j)]

E = kq/a²[2(sin 60j)] = 1.732 kq/a²

Thus, the location of a point where the electric field is zero is at the center of the triangle which is equal to ¹/₆√3a.

The magnitude and direction of the electric field at the top corner due to the two charges at the base is  1.732 kq/a².

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

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Darya [45]

To answer the two questions, we need to know two important equations involving centripetal movement:

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a = \frac{v^{2}}{r}

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v = ((1800*2π) / 60) * 0.26

Wait. 2π? 0.26? 60? Let's break down why these numbers are written differently. In order to use the equation v = ωr, it is important that the units of ω is in radians. Since one revolution is equivalent to 2π radians, we can easily do the conversion from revolutions to radians by multiplying it by 2π. As for 0.26, note that the question asks for the units to be m/s. Since we need meters, we simply convert 26 cm, our radius, into meters. The revolutions is also given in revs/min, and we need to convert it into revs/sec so that we can get our final units correct. As a result, we divide the rate by 60 to convert minutes into seconds.

Back to the equation:

v = ((1800*2π)/60) * 0.26

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Now that we know the linear velocity, we can find the centripetal acceleration:

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Wow! That's fast!

<u>We now have our answers for a and b:</u>

a. 49 (m/s)

b. 9.2 * 10^{3} (m/s^{2})

If you have any questions on how I got to these answers, just ask!

- breezyツ

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2 years ago
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Let the position where net field is zero will lie at distance "r" from q1

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