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nata0808 [166]
3 years ago
13

Which element would you expect to form an ionic compound when combined with bromine (Br)?

Chemistry
2 answers:
gladu [14]3 years ago
4 0
I know this isn't much help, but I have a few elements I think it might be:

 1) Al

 2) Fe

 3) I

 4) K

daser333 [38]3 years ago
3 0
Ionic bond is formed due to the transfer of electrons from one atom to another so that all atoms involved in the bond would become stable (with 8 electrons in the outermost level)

Now, for bromine, it has 35 electrons. This means that bromine has 7 valence electrons in the outermost level. Therefore, bromine needs to gain one electron in order to become stable.

Bromine can react with elements from:
group 1: each element in group 1 needs to lose one electron to become stable. Therefore, one bromine atom can form an ionic bond when combined with an atom of an element from group 1 (element in group 1 loses its electron for bromine atom).
group 2: each element in group 2 needs to lose two electrons to become stable. Therefore, two bromine atoms can form ionic bonds when combined with an atom of an element from group 2 (element in group 2 loses two electrons, one for each bromine atom).
group 3: each element in group 3 needs to lose three electrons to become stable. Therefore, three bromine atoms can form ionic bonds when combined with an atom of an element from group 1 (element in group 3 loses three electrons, one for each bromine atom).

Since no choices are given , I cannot tell the exact choice. But the correct one would be the element from either group 1 , 2 or 3.
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When large masses of magma solidify very slowly far below earths surface, they form igneous rocks that have a ___?
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The answer is; D,

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for number less than 0.1, such as 0.06, the zeros to the right of the decimal point but before the first nonzero digit
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For the number less than 0.1 such as 0.006, the zeroes to the right of the decimal point but before the first non zero digit show the decimal place of the first significant digit.

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There is only one significant figure in the provided number 0.06. The decimal place of the first digit is indicated by the zeros that appear to the right of the decimal point but before the first non-zero digit.

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1 year ago
What is the concentration of a solution formed by mixing 89.94 grams of cobalt (II)
bezimeni [28]

Answer:

0.47 M

Explanation:

The concentration of the solution can be calculated using the following equation:

C = \frac{\eta}{V} = \frac{m}{M*V}

<u>Where:</u>

V: is the volume of the solution = 68.6x10⁻² L

η: is the moles of cobalt (II)  sulfate

m: is the mass of cobalt (II)  sulfate = 89.94 g

M: is the molar mass of cobalt (II)  sulfate = 281.103 g/mol

The concentration of cobalt (II)  sulfate is:

C = \frac{m}{M*V} = \frac{89.94 g}{281.103 g/mol*68.6 \cdot 10^{-2} L} = 0.47 mol/L

We used the molar mass of the cobalt (II)  sulfate heptahydrate (281.103 g/mol) since it is one of the most common salts of cobalt.

Therefore, the concentration of a solution of cobalt (II)  sulfate is 0.47 M (assuming that the cobalt (II)  sulfate is heptahydrate).

I hope it helps you!

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