Answer: The correct answer is option (C).
Explanation:
Law of reflection:
- Angle of incident is equal to angle of reflection;∠i=∠r
- Incident ray, reflected ray and normal to the reflecting interface at the point of incidence all lie in same plane.
When light ray from candle strikes a mirror at an angle of 40° with the normal, then the angle at which ray reflected back will 40°.
The answer is B I took the test a while back
Question: In which situation would a space probe most likely experience centripetal acceleration?
as it revolves around a planet
as it flies straight past a moon
as it is pulled in a line toward the Sun
as it lifts off from Earth
Answer:
When "space probe revolves around a planet" most likely to experience centripetal acceleration
Explanation:
Centripetal acceleration defined as the rate in change of tangential velocity. Also, as per Newton's second law, any kind of force will be directly proportional to the acceleration attained by the object. So, for centripetal acceleration, the force will be the centripetal force. The centripetal force will be acting on an object rotating in a circular motion with its direction of force towards the center. Thus, centripetal acceleration will be experienced by an object or a space probe when it is in a circular motion. It means the space probe is revolving around a planet.
Answer:
B = - 1.51 10⁻⁷ T
Explanation:
For this exercise we can use Faraday's law of induction
E = - 
In this case, they indicate that the normal and the magnetite field are in the same direction, so the angle is zero (cos 0 = 1), they give the area of the loop A = 4.32 10⁻⁴ m² and since we have N = 1470 turns in each one a voltage is induced
E = - N B A
B = -E A / N (1)
we find the induced voltage with ohm's law
V = i R
where the current is defined by
i = Q / t
we substitute
V = Q R / t
let's calculate
V = 9.18 10-3 56.0 / t
We must assume a time normally is t = 1 s
V = 0.514 V
this is the voltage in the circuit which must be the induced voltage V = E
we substitute in 1
B = - 0.514 4.32 10⁻⁴ / 1470
B = - 1.51 10⁻⁷ T
Answer:
230.4kg
Explanation:
volume of the room = l× b×h
volume= 8×6×4
volume=192m3
density= mass/volume
hence mass= density × volume
mass= 1.2kgm-3 × 192m3
mass= 230.4kg
