Answer:
What do you need help with?!
Explanation:
It’s the 3 one
Also I think it’s suppose to be
a
b
c
d
110
both sugar and phosphate molecules
The answer is 0.405 M/s
- (1/3) d[O2]/dt = 1/2 d[N2]/dt
- d[O2]/dt = 3/2 d[N2]/dt
- d[O2]/dt = 3/2 × 0.27
- d[O2]/dt = 0.405 mol L^(-1) s^(-1)
