1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elis [28]
2 years ago
12

Can yall assist me with this lab? It is really screwing me up... No spam!! the only part that I need is the last page. I will ma

rk brainliest if you get it right.
Chemistry
1 answer:
kenny6666 [7]2 years ago
5 0

Answer:

What do you need help with?!

Explanation:

You might be interested in
Based on your solubility rules which of the following compounds would form a precipitate water?
Novosadov [1.4K]
H2SO4+NaOH=Na2SO4+H2O
3 0
3 years ago
Physicist Richard Feyneman used to say, "Science is a way of trying not to
Leokris [45]

Answer:

nope

Explanation:

nopeee

6 0
3 years ago
I need help, I don't understand the question
Oduvanchick [21]
Remember this. 

Ionic molecules has ionic bonds
Nonpolar molecules has dispersion (Van del Waals)
Polar molecules could either have hydrogen bonding or Dipole-Dipole. Hydrogen bonding is when you have F, O or N with H, every other polar molecule is dipole-dipole.

a. polar- dipole-dipole
b. polar- hydrogen bonding
c. nonpolar- dispersion
d. nonpolar- dispersion
e. polar- dipole-dipole
f. polar-dipole-dipole
g. nonpolar- dispersion
h. polar- hydrogen bonding.
3 0
3 years ago
c. The reaction Br2 (l) --> Br2 (g) has ΔH = 30.91 kJ/mol and ΔS = 93.3 J/mol·K. Use this information to show (within close a
egoroff_w [7]

Answer:

The answer to your question is given below.

Explanation:

From the question given above, the following data were obtained:

Br₂ (l) —> Br₂(g)

Enthalpy change (ΔH) = 30.91 KJ/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

Next, we shall convert 30.91 KJ/mol to J/mol. This can be obtained as follow:

1 KJ/mol = 1000 J/mol

Therefore,

30.91 KJ/mol = 30.91 × 1000

30.91 KJ/mol = 30910 J/mol

Thus, 30.91 KJ/mol is equivalent to 30910 J/mol.

Finally, we shall determine the boiling temperature of bromine. This can be obtained as follow:

Enthalpy change (ΔH) = 30910 J/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

ΔS = ΔH / T

93.3 = 30910 / T

Cross multiply

93.3 × T = 30910

Divide both side by 93.3

T = 30910 / 93.3

T = 331.29 K

Thus, the boiling temperature of bromine is 331.29 K

6 0
3 years ago
Repeated trials and replication are the same thing. <br><br> - True<br> - False
Sauron [17]

Answer:

false

Explanation:

get a good grade :)

4 0
3 years ago
Other questions:
  • What volume of beaker contains exactly 2.23x10^-2 mol of nitrogen gas at STP?
    6·1 answer
  • One similarity between all mixtures and compounds is that both(1) are heterogeneous(2) are homogeneous(3) combine in a definite
    5·2 answers
  • Which factor distinguishes a metallic bond from an ionic?
    12·1 answer
  • The chemical equation for a reaction between K2Cr2O7 and HCl is shown. K2Cr2O7 + 14HCl → 2CrCl3 + 2KCl + 3Cl2 + 7H2O
    12·1 answer
  • What does variable mean in a science project.
    8·2 answers
  • A____is a prediction about the outcome of a test or experiment.
    13·2 answers
  • In a chemical equation what name does the left side have
    9·1 answer
  • Suppose you are trying to find the volume of a box based on the following measurements for the length, width, and height of the
    12·1 answer
  • The electrons in the outermost energy level are responsible for the atoms _____. These electrons are called the _______ electron
    10·1 answer
  • Please help! Is there another way that 3.40x10^-19J can be imputed on a computer. I have the right answer but it is wrong.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!