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erma4kov [3.2K]
3 years ago
8

Calculate the volume in milliliters of a 1.3M zinc nitrate solution that contains 100.g of zinc nitrate ZnNO32. Be sure your ans

wer has the correct number of significant digits.
Chemistry
1 answer:
zheka24 [161]3 years ago
3 0

Answer:

The volume is 406 mL

Explanation:

Step 1: Data given

Molarity of a zinc nitrate solution = 1.3 M

Mass of zinc nitrate = 100 grams

Molar mass of Zn(NO3)2 = 189.36 g/mol

Step 2: Calculate moles Zn(NO3)2

Moles Zn(NO3)2 = mass Zn(NO3)2 / molar mass Zn(NO3)2

Moles Zn(NO3)2 = 100.0 grams / 189.36 g/mol

Moles Zn(NO3)2 = 0.5281 moles

Step 3: Calculate volume

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.5281 moles / 1.3 M

Volume = 0.406 L = 406 mL

The volume is 406 mL

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How much heat is added if 0.0318g of water is increased in temperature by 0.364 degrees C?
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Answer:

0.04838J

Explanation:

Heat is a form of energy that is transferred from one body to another as the result of a difference in temperature between the bodies , here heat is added to the water as a result of temperature change of 0.364 degreesC

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How many moles are 21.67 L of NH4CI?
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Answer:

0.967mole

Explanation:

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Volume of NH₄Cl  = 21.67L

Unknown:

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