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4 years ago

What is the formula for potassium iodide

Physics

2 answers:

RoseWind [281]4 years ago

6 0

The formula for potassium iodide is PI

musickatia [10]4 years ago

3 0

Potassium iodide

Molar mass: 166.0028 g/mol

Formula: KI

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The elastic extensibility of a piece of string is .08. If the string is 100 cm long, how long will the string be when it is stre

Ksju [112]

Answer:

The elastic extensibility of a piece of string is .08. If the string is 100 cm long, how long will the string be when it is stretched to the point where it becomes plastic? is your ansewer dont take tension

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3 years ago

A heavy turntable, used for rotating large objects, is a solid cylindrical wheel that can rotate about its central axle with neg

scoundrel [369]

Answer:

a) $I = 113.014\,kg\cdot m^{2}$ , b) $m = 2075.556\,kg$

Explanation:

a) The turntable has the following physical model by using Newton's laws:

$F \cdot R = I \cdot \alpha$

The moment of inertia is:

$I = \frac{F\cdot R}{\alpha}$

$I = \frac{(300\,N)\cdot(0.33\,m)}{0.876\,\frac{rad}{s^{2}} }$

$I = 113.014\,kg\cdot m^{2}$

b) The moment of inertia for a solid cylinder:

$I = \frac{1}{2}\cdot m \cdot R^{2}$

The mass of the turntable is:

$m = \frac{2 \cdot I}{R^{2}}$

$m = \frac{(2)\cdot (113.014\,kg\cdot m^{2})}{(0.33\,m)^{2}}$

$m = 2075.556\,kg$

8 0

3 years ago

Two very long uniform lines of charge are parallel and are separated by 0.300 m. each line of charge has charge per unit length

Alenkasestr [34]

linear charge density of system of two line charges is given as

$\lambda = 5.20 \muC/m$

now as we know that electric field due to a line charge at some distance from it is given by

$E = \frac{\lambda}{2\pi \epsilon_0 r}$

so here we will first find the electric field of first line charge at the position of other line charge

$E = \frac{5.20 * 10^{-6}}{2 \pi * 8.85 * 10^{-12}* 0.300}$

$E = 312000 N/C$

now as we know that

$F = qE$

here q = charge on the line charge system at which force is required

E = electric field on that system of charge where force is required

now we can find the charge by

$q = \lambda * L$

$q = 5.20 * 10^{-6}* 0.05 = 0.26 * 10^{-6} C$

Now using the above formula

$F = qE$

$F = 0.26 * 10^{-6} * 312000$

$F = 0.0811 N$

so force on the part of wire is F = 0.0811 N

8 0

3 years ago

If you have 4 kg of a sample with density of 1 897 g/ml what is the volume

Kaylis [27]

We know, Volume = Mass / Density
Here, mass = 4 Kg = 4000 g
d = 1,897 g/ml

Substitute their values,
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v = 2.108 ml

In short, Your Answer would be 2.108 mL

Hope this helps!

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3 years ago

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Umnica [9.8K]

Answer:

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