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DanielleElmas [232]
3 years ago
12

Suppose that we replace the aluminum with a mystery metal and repeat the experiment in the video. As in the video, the mass of t

he metal is the same as that of the water. Room temperature is about 20∘C before the start of the experiment. The water heats up to 40∘C, and the mystery metal heats up to 80∘C. Compared to that of water, the heat capacity of our mystery metal is
Physics
1 answer:
katrin2010 [14]3 years ago
7 0

Answer: b) one-third as great.

Explanation:

The options include:

a) three times greater.

b) one-third as great.

c) half as great.

d) two times greater.

e) the same.

Since the water heats up to 40°C and the room temperature is about 20°C before the start of the experiment, heat absorbed will be: (40°C-20°C).= 20°C

Since mystery metal heats up to 80∘C and the room temperature is about 20°C before the start of the experiment, heat absorbed will be: (80°C-20°C).= 60°C.

Therefore, based on the calculation, when compared to that of water, the heat capacity of our mystery metal is (20/60) = 1/3 one-third as great.

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Answer:

The water level rises more when the cube is located above the raft before submerging.

Explanation:

These kinds of problems are based on the principle of Archimedes, who says that by immersing a body in a volume of water, the initial water level will be increased, raising the water level. That is, the height in the container with water will rise in level. The difference between the new volume and the initial volume of the water will be the volume of the submerged body.

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F_{B}=W=Ro_{H20}*g*Vs\\W = (200+730)*9.81\\W=9123.3[N]\\\\9123=1000*9.81*Vs\\Vs = 0.93 [m^3]

Vs > Vc, What it means is that the combined volume of the raft and the cube is greater than that of the cube at the bottom of the pool. Therefore the water level rises more when the cube is located above the raft before submerging.

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An astronaut on Pluto attaches a small brass ball to a 1.00-m length of string and makes a simple pendulum. She times 10 complet
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T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2

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