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3 years ago

Which type of electromagnetic radiation carries the most energy and has the highest frequency?

Physics

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

Gamma rays

Explanation:

Gamma rays is at the end of the electromagnetic spectrum, and has the highest energy. It propagates through space at 3x10^8 m/s and has the smallest wavelength and the highest frequency. It is given off by atoms of element as they undergo nuclear disintegration.

IgorC [24]3 years ago

4 0

Answer:

Gamma radiation carries the most energy since it has the highest frequency.

Explanation:

Electromagnetic radiations are waves which do not require material medium for their propagation and they are arranged in electromagnetic spectrum according to their increasing frequency and decreasing wavelength or decreasing frequency and increasing wavelength.

Examples of Electromagnetic radiations, in terms of decreasing frequency and increasing wavelength:

Gamma rays > x-ray > ultraviolet ray > visible light > infrared > micro waves > radio waves

Energy of wave is related to frequency using the following formula:

E = hf

where:

h is Planck's constant and

f is frequency of the wave

From the illustration above, gamma radiation carries the most energy since it has the highest frequency.

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3 years ago

A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.

JulsSmile [24]

Answer:

$\mu =0.75$

Explanation:

<u>Frictional Force </u>

When the car is moving along the curve, it receives a force that tries to take it from the road. It's called centripetal force and the formula to compute it is:

$F_c=m.a_c$

The centripetal acceleration a_c is computed as

$\displaystyle a_c=\frac{v^2}{r}$

Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one

$F_c=m.\frac{v^2}{r}$

For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as

$F_r=\mu N$