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prohojiy [21]
4 years ago
15

Which type of electromagnetic radiation carries the most energy and has the highest frequency?

Physics
2 answers:
jek_recluse [69]4 years ago
8 0

Answer:

Gamma rays

Explanation:

Gamma rays is at the end of the electromagnetic spectrum, and has the highest energy. It propagates through space at 3x10^8 m/s and has the smallest wavelength and the highest frequency. It is given off by atoms of element as they undergo nuclear disintegration.

IgorC [24]4 years ago
4 0

Answer:

Gamma radiation carries the most energy since it has the highest frequency.

Explanation:

Electromagnetic radiations are waves which do not require material medium for their propagation and they are arranged in electromagnetic spectrum according to their increasing frequency and decreasing wavelength or decreasing frequency and increasing wavelength.

Examples of Electromagnetic radiations, in terms of decreasing frequency and increasing wavelength:

Gamma rays > x-ray > ultraviolet ray > visible light > infrared > micro waves > radio waves

Energy of wave is related to frequency using the following formula:

E = hf

where:

h is Planck's constant and

f is frequency of the wave

From the illustration above, gamma radiation carries the most energy since it has the highest frequency.

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A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 35.5 m/s. a) What is the coeff
postnew [5]

Answer:

The coefficient of friction present between the roadway and the wheels of the truck is <u>0.833</u>.

Explanation:

Given:

Radius of the curve (R) = 150 m

Maximum speed of truck (v) = 35.5 m/s

Let the coefficient of friction between the roadway and the wheels of the truck be "μ".

As the truck is moving around a circular curve. So, the force acting on it is centripetal force which acts in the radial inward direction towards the center of the circular curve.

The centripetal force acting on the truck is given as:

F_c=\frac{mv^2}{R}

Now, the friction between the roadway and the wheels of the truck is responsible for providing the necessary centripetal force. So, frictional force is equal to the centripetal force necessary for circular motion.

Frictional force is given as:

f=\mu N

Where, 'N' is the normal force. Since there is no vertical motion, the normal force is equal to weight of truck. So,

N=mg

Therefore, frictional force, f=\mu mg

Now, frictional force = centripetal force

f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu = \frac{v^2}{Rg}

Plug in the given values and solve for 'μ'. This gives,

\mu=\frac{(35\ m/s)^2}{(150\ m)(9.8\ m/s^2)}\\\\\mu=\frac{1225\ m^2/s^2}{1470\ m^2/s^2}\\\\\mu=0.833

Therefore, the coefficient of friction present between the roadway and the wheels of the truck is 0.833

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4 years ago
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FALSE this is not true

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