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3 years ago

Which type of electromagnetic radiation carries the most energy and has the highest frequency?

Physics

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

Gamma rays

Explanation:

Gamma rays is at the end of the electromagnetic spectrum, and has the highest energy. It propagates through space at 3x10^8 m/s and has the smallest wavelength and the highest frequency. It is given off by atoms of element as they undergo nuclear disintegration.

IgorC [24]3 years ago

4 0

Answer:

Gamma radiation carries the most energy since it has the highest frequency.

Explanation:

Electromagnetic radiations are waves which do not require material medium for their propagation and they are arranged in electromagnetic spectrum according to their increasing frequency and decreasing wavelength or decreasing frequency and increasing wavelength.

Examples of Electromagnetic radiations, in terms of decreasing frequency and increasing wavelength:

Gamma rays > x-ray > ultraviolet ray > visible light > infrared > micro waves > radio waves

Energy of wave is related to frequency using the following formula:

E = hf

where:

h is Planck's constant and

f is frequency of the wave

From the illustration above, gamma radiation carries the most energy since it has the highest frequency.

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An inflatable raft (unoccupied) floats down a river at an approximately constant speed of 5.6 m/s. A child on a bridge, 71 m abo

saveliy_v [14]

Answer:

21.28 m

Explanation:

height, h = 71 m

velocity of raft, v = 5.6 m/s

let the time taken by the stone to reach to raft is t.

use second equation of motion for stone

$h = ut + \frac{1}{2}at^{2}$

u = 0 m/s, h = 71 m, g = 9.8 m/s^2

71 = 0 + 0.5 x 9.8 x t^2

t = 3.8 s

Horizontal distance traveled by the raft in time t

d = v x t = 5.6 x 3.8 = 21.28 m

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2 years ago

A 60cm long string of an ordinary guitar is tuned to produce the note a4 (frequency 440hz) when vibrating in its fundamental mod

pishuonlain [190]

Answer:

0.78 m

Explanation:

The relationship between wavelength and frequency of a wave is given by

$v=f \lambda$

where

v is the speed of the wave

f is the frequency

$\lambda$ is the wavelength

For the sound wave in this problem, we have

$f=440 Hz$ is the frequency

v = 344 m/s is the speed of sound in air

Substituting into the equation and re-arranging it, we find the wavelength:

$\lambda=\frac{v}{f}=\frac{344 m/s}{440 Hz}=0.78 m$

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