Velocity of molecules within a body
Answer:
(a) The horizontal ground reaction force ![F_{g,x}=325\, N](https://tex.z-dn.net/?f=F_%7Bg%2Cx%7D%3D325%5C%2C%20N)
(b) The vertical ground reaction force ![F_{g,y}=696\, N](https://tex.z-dn.net/?f=F_%7Bg%2Cy%7D%3D696%5C%2C%20N)
(c) The resultant ground reaction force ![F_g=768\, N](https://tex.z-dn.net/?f=F_g%3D768%5C%2C%20N)
Explanation:
Given
John mass , m = 65 kg
Horizontal acceleration , ![a_x= 5.0 \frac{m}{s^{2}}](https://tex.z-dn.net/?f=a_x%3D%205.0%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
Vertical acceleration , ![a_y=0.9 \frac{m}{s^{2}}](https://tex.z-dn.net/?f=a_y%3D0.9%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
(a) Using Newton's 2nd law in horizontal direction
![F_{g,x}=ma_x](https://tex.z-dn.net/?f=F_%7Bg%2Cx%7D%3Dma_x)
=>![F_{g,x}=65\times 5\, N=325\, N](https://tex.z-dn.net/?f=F_%7Bg%2Cx%7D%3D65%5Ctimes%205%5C%2C%20N%3D325%5C%2C%20N)
Thus the horizontal ground reaction force ![F_{g,x}=325\, N](https://tex.z-dn.net/?f=F_%7Bg%2Cx%7D%3D325%5C%2C%20N)
(b) Using Newton's 2nd law in vertical direction
![F_{g,y}-mg=ma_y](https://tex.z-dn.net/?f=F_%7Bg%2Cy%7D-mg%3Dma_y)
=>![F_{g,y}=mg+ma_y](https://tex.z-dn.net/?f=F_%7Bg%2Cy%7D%3Dmg%2Bma_y)
=>![F_{g,y}=65\times (9.81+0.9)\, N=696\, N](https://tex.z-dn.net/?f=F_%7Bg%2Cy%7D%3D65%5Ctimes%20%289.81%2B0.9%29%5C%2C%20N%3D696%5C%2C%20N)
Thus the vertical ground reaction force ![F_{g,y}=696\, N](https://tex.z-dn.net/?f=F_%7Bg%2Cy%7D%3D696%5C%2C%20N)
(c) Resultant ground reaction force is
![F_g=(F_{g,x}^{2}+F_{g,y}^{2})^{\frac{1}{2}}](https://tex.z-dn.net/?f=F_g%3D%28F_%7Bg%2Cx%7D%5E%7B2%7D%2BF_%7Bg%2Cy%7D%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
=>![F_g=(325^{2}+696^{2})^{\frac{1}{2}}\, N=768\, N](https://tex.z-dn.net/?f=F_g%3D%28325%5E%7B2%7D%2B696%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%2C%20N%3D768%5C%2C%20N)
=>![F_g=768\, N](https://tex.z-dn.net/?f=F_g%3D768%5C%2C%20N)
Thus the resultant ground reaction force ![F_g=768\, N](https://tex.z-dn.net/?f=F_g%3D768%5C%2C%20N)
Its larger and if u where wondering to positive ions are smaller
H<span>igh voltage demonstrations!</span>