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Andrei [34K]
3 years ago
8

two students are working together to build a birdhouse. Student 1 applies a force of 10 N to a wooden board in order to slide it

across the table to student 2. If the force of fraction resisting the student ´s push is 4 N, what is the net force acting on the board?
Chemistry
1 answer:
Ganezh [65]3 years ago
5 0

Answer:

6

Explanation:

if there is 10n and the friction is 4n on the table then it is 6n.

i hope this helps you! :)

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Answer : The time passed in years is 2.83\times 10^3\text{ years}

Explanation :

Half-life = 5730 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5730\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = X g

a - x = amount left after decay process = 71\% \times (x)=\frac{71}{100}\times (X)=0.71Xg

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{X}{0.71X}

t=2831.00\text{ years}=2.83\times 10^3\text{ years}

Therefore, the time passed in years is 2.83\times 10^3\text{ years}

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