All categories

3 years ago

How many electrons are there in second principal energy level(n=2) of a phosphorus atom?

Chemistry

1 answer:

salantis [7]3 years ago

6 0

Answer:

8 electrons

Explanation:

Phosphorous is the element of group 15 and third period. The atomic number of chlorine is 15 and the symbol of the element is P.

The electronic configuration of the element phosphorus is:-

$1s^22s^22p^63s^23p^3$

Thus, from the electronic configuration shown above,

In n = 2, the total number of electrons are 8 which are present in $2s^22p^6$

You might be interested in

If the mass of an object is 60.0 grams and the density of the object is 15.0 g/mL, what is the volume of the object? The formula

laila [671]

Answer:

168.56 mL

Explanation:

density = mass/volume, use basic algebra skills to replace the volume and solve

7 0

2 years ago

Help me please<br> ( I'll give brainlist to whoever answers right)

devlian [24]

A goes with u, C with G, and T with A

4 0

3 years ago

On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35Cl and 86.15 % for 37Cl. What

diamong [38]

Answer:

36.693

Explanation:

From the question given, the following were obtained:

Let 35Cl be isotope A and 37Cl be isotope

For isotope A (35Cl),

Mass number = 34.9700

Abundance = 13.85 %

For isotope B (37Cl),

Mass number = 36.9700

Abundance = 86.15 %

Atomic mass =

[( Mass of AxAbundance A)/100] + [(Mass of BxAbundance B)/100]

[(34.97x13.85)/100] + [(36.97x86.15)/100]

= 36.693

6 0

3 years ago

Determine the mass of 1 mol of gold (Au), of aluminum chloride (AlCl3), and of glucose (C6H12O6)

sleet_krkn [62]

Answer: Mass of 1 mol of gold (Au) is 197g , of aluminum chloride $(AlCl_3)$ is 133.5 g and of glucose $(C_6H_{12}O_6)$ is 180 g

Explanation: Mass of 1 mole of a substance is called its molar mass.

a) 1 mole of $Au$ contains $6.023\times 10^{23}atoms$ and weigh 197g.

b) 1 mole of $AlCl_3$ will weigh= $1\times {\text {mass of 1 mole of Aluminium}}+3\times {\text {mass of 1 mole of chlorine atom}}$

Thus mass of 1 mole of $AlCl_3$ will be $=1moles\times {27g/mol}+3moles\times {35.5g/mol}=133.5g$

c) 1 mole of $C_6H_{12}O_6$ will weigh= $6\times {\text {mass of 1 mole of carbon}}+12\times {\text {mass of 1 mole of hydrogen atom}}+6\times {\text {mass of 1 mole of oxygen}}$

1 mole of $C_6H_{12}O_6$ will weigh= $6\times 12g/mol+12\times 1g/mol+6\times 16g/mol=180g$

5 0

3 years ago

Select all that apply.

prohojiy [21]

My guess is the last 2... <span>phosphorus and potassium</span>

5 0

3 years ago

Read 2 more answers