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jolli1 [7]
3 years ago
10

Compute each quotient using the identities you discovered in this lesson.x^4-16/x-2

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0

Answer:

The quotient will be (x^2+4)(x+2)

Step-by-step explanation:

We have given the equation \frac{x^4-16}{x-2}

We have to find the quotient

From algebraic equation we know that a^2-b^2=(a+b)(a-b)

So \frac{x^4-16}{x-2}=\frac{(x^2)^2-4^2}{x-2}=\frac{(x^2+4)(x^2-4)}{x-2}=\frac{(x^2+4)(x+2)(x-2)}{x-2}=(x^2+4)(x+2)

So the quotient will be (x^2+4)(x+2)

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Use quadratic method :<br> 6y^2 - 4y - 3=
Naya [18.7K]

Answer:

see explanation

Step-by-step explanation:

look at the photo

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B833%7D%20" id="TexFormula1" title=" \sqrt[5]{833} " alt=" \sqrt[5]{833} "
zepelin [54]
Here is the simplified answer to this equation: 5 goes into 8 once, so you would bring the 5 on top and subtract 8, the first number, by 5. The answer is three. Bring down the 3 next to the 8. You now have 33. 5 goes into 33 6 times, which equals 30. Write 30 underneath 33 and bring the 6 to the top next to the 1. Bring down the 3 next to the last 3. You now have 33. 5 goes into 33 (once again) 6 times. Write 6 on top next to the last 6. 33 - 30 = 3. 5 cannot go into 3 since it is larger, so 3/5 you write 3/5 as a decimal next to 166 at the top (3 at the bottom and 5 is the larger number at the divisor spot). The decimal is 0.6. Therefore, your answer should be 166.6. To make sure, multiply 166.6 x 5. Hopefully, you get 833.

Hope I helped!
4 0
3 years ago
Help me with question 4 and 5
lisov135 [29]

Answer:

2.6768·10^(-14)  (Answer C)

Step-by-step explanation:

Problem 4:  We ADD the powers of 10:  10^6·10^(-3) = 10^3.  Also, 3.6·1.7 = 6.12.  Therefore, Answer D is correct.

Problem 5:  Again we ADD (combine) the powers of 10:  10^(-10)·10^(-5) =

10^(-15).  4.78·5.6 = 26.768.  Our intermediary answer is thus:

26.768·10^(-15).  This must be rewritten in the form x.xxxx, so here we have:

2.6768·10^(-14)  (Answer C)

3 0
3 years ago
Which equation matches the graph of the absolute value function seen here?
skad [1K]

Answer:

please give image

Step-by-step explanation:

3 0
3 years ago
In ΔNOP, \overline{NP} NP is extended through point P to point Q, \text{m}\angle PNO = (x+14)^{\circ}m∠PNO=(x+14) ∘ , \text{m}\a
adelina 88 [10]

Answer:

<OPQ = 23 degrees

Step-by-step explanation:

Given

Interior angles m∠PNO=(x+14) and m∠NOP=(x−1)

Exterior angle = m<OPQ = (5x-2)

The sum of interior angles is equal to the exterior angle, that is;

m∠PNO+m∠NOP = m<OPQ

x+14 + x-1 = 5x-2

2x + 13 = 5x-2

Collect like terms;

2x-5x = -2-13

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x = 15/3

x = 5

Get <OPQ

<OPQ = 5x - 2

<OPQ = 5(5)- 2

<OPQ = 25-2

<OPQ = 23 degrees

4 0
3 years ago
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