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jolli1 [7]
2 years ago
10

Compute each quotient using the identities you discovered in this lesson.x^4-16/x-2

Mathematics
1 answer:
luda_lava [24]2 years ago
8 0

Answer:

The quotient will be (x^2+4)(x+2)

Step-by-step explanation:

We have given the equation \frac{x^4-16}{x-2}

We have to find the quotient

From algebraic equation we know that a^2-b^2=(a+b)(a-b)

So \frac{x^4-16}{x-2}=\frac{(x^2)^2-4^2}{x-2}=\frac{(x^2+4)(x^2-4)}{x-2}=\frac{(x^2+4)(x+2)(x-2)}{x-2}=(x^2+4)(x+2)

So the quotient will be (x^2+4)(x+2)

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18.<br> What is the solution of |2x+5|&lt;19?<br> -19 &lt; x &lt; 19<br> -12 -7 -24 &lt; x &lt; 14
elena-14-01-66 [18.8K]

Answer:

thats a tough one

Step-by-step explanation:

4 0
3 years ago
The larger of two numbers is 15 more than three times the smaller number. If the sum of the two numbers is 63, find the numbers.
tangare [24]
The larger number is 51 and the smaller number is 12. ( hope I helped) have a good day
3 0
3 years ago
last week, ezra's sold 1/3 of tangerines and Anthony sold 3/4 of tangerines as ezra's did. how many boxes of tangerines did Anth
Bond [772]

Answer:

¼ box

Step-by-step explanation:

Ezra sold ⅓ box of tangerines.

Anthony sold ¾ as many as Ezra               = ¾ × ⅓ box

Cancel the 3s                                               = ¼ × ¹/₁ box

Multiply numerators and denominators     = ¼ box

Anthony sold ¼ box of tangerines.

6 0
3 years ago
Parent function of h(x)=|x+5|-2
gavmur [86]

Answer:

g(x)=|x|

Step-by-step explanation:

3 0
3 years ago
Check all of the ordered pairs that satisfy the equation below.y=2/5x
zvonat [6]

We are going to do this step by step:

Let's start with option A

A.

X = 25 and Y = 5/2

y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10

In this case, when X = 25 , then Y = 10 ,which is different to 5/2

B.

X = 14 , Y = 35

y=\frac{2}{5}\cdot14=\frac{28}{5}

In case, when X = 14, then Y = 28/5, which is different to 35

C.

X = 40 , Y = 24

y=\frac{2}{5}\cdot40=\frac{80}{5}=16

Similarly, in this case, when X = 40, then Y = 16, which is different to 24

D.

X = 10 , Y=4

y=\frac{2}{5}\cdot10=\frac{20}{5}=4

Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y

E.

X = 50 , Y = 20

y=\frac{2}{5}\cdot50=\frac{100}{5}=20

In this case, the values of Y are also the same.

F.

X = 30 , Y = 12

y=\frac{2}{5}\cdot30=\frac{60}{5}=12

Again, in this case, the values of Y are the same, so the pair satisfies the equation.

In conclusion: options D, E and F satisfy the equation

3 0
1 year ago
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