Answer:
Formation volume factor = 1.36
The solution gas-oil ratio = 0.00356
Explanation:
Given Data;
Volume of oil reservoir = 227.0 cc
Volume of oil in the tank = 167.4 cc
Separator production = 0.537 scf
Stock tank production = 0.059 scf
formation volume factor of the oil =?
The solution gas-oil ratio = ?
1. Formation volume factor is calculated using the formula;
Formation volume factor = volume of oil reservoir/volume of oil stock tank
Substituting, we have
Formation volume factor = 227.0/ 167.4
= 1.36
2. The solution gas-oil ratio can be calculated using the formula;
The solution gas-oil ratio= total gas in scf/volume of stock tank
= (0.537 + 0.059)/167.4
= 0.596/167.4
=0.00356
Wood is a suspension.
The easiest way I believe to find out whether a substance is a colloid or a suspension is determining is determining if the particles in a substance separate when sitting still. Unlike those in a suspension, particles in a colloid do not separate when sitting still.
Hope this helped!
Answer:
= 1 X 10⁻⁻¹²M
Explanation:
At 25°C & 1atm [H⁺][OH⁻] = 1 x 10⁻¹⁴ => [H⁺] = 1 X 10⁻¹⁴/[OH⁻] = 1 X 10⁻¹⁴/1 X 10⁻²
= 1 X 10⁻⁻¹²M
mass of carbonic acid = 300g
molar mass of H2CO3 = 2H + C + 3 O
= 2 x 1.008+ 12.01 + 3 x 16
= 62.03g/mol
moles of H2CO3 = mass/Molar mass
= 300/62.03
= 4.8364 moles
1 mole H2CO3 has 3 moles Oxygen
4.8364 moles H2CO3 contains
= 3 x 4.8364 moles Oxygen = 14.509 moles Oxygen
moles = mass/Molar mass
mass of oxygen = moles x Molar mass of Oxygen
= 14.509 x 16
= 232.15g Oxygen
mass of oxygen in 300g of carbonic acid(H2CO3) = 232.15g
Answer:
mass and height of the object.
