Answer:
Molarity of NaOH = 0.025 M
Explanation:
Given data:
Molarity of HCl = C₁ = 0.05 M
Volume of HCl = V₁= 50 mL
Molarity of NaOH = C₂=?
Volume of NaOH =V₂= 100 mL
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Molarity of HCl
V₁ = Volume of HCl
C₂ = Molarity of NaOH
V₂ = Volume of NaOH
Now we will put the values:
C₁V₁ = C₂V₂
0.05 M × 50 mL = C₂ × 100 mL
2.5 M.mL =C₂ × 100 mL
C₂ = 2.5 M.mL /100 mL
C₂ = 0.025 M
Answer:
The mass of reactants and products are equal hence the reaction obeys law of conservation of mass
Explanation:
The law of mass conservation states that for a closed system to all transfer of mass, the mass of system must remain constant over time. This means for a chemical reaction, the mass of reactants must equal the mass of products.
if 2.796g of Zn reacts with 2.414g of sulphur to produce 4.169g of ZnS ad 1.041g of unreacted sulphur, then it means that accorfing to the law of mass conservation, the mass of reactants (zinc and sulphur), must be equal to mass of products (zinc sulfide and unreacted sulphur)
Mass of reactants = 2.796g + 2.414g =5.21g
Mass of products = 4.169g + 1.041g=5.21g
Answer:
Decomposition of aluminium oxide forms aluminium atoms and oxygen atoms.
Explanation:
<u>Decomposition reaction:</u>
When a single compound break down into two or more simpler products.
For example "AB" reactant undergoes decomposition to form "A" and "B" products.
The chemical reaction is as follows.

The given compound is aluminium oxide.
The decomposition reaction of aluminium oxide is a follows.

The balanced equation is as follows.

Therefore, Decomposition of aluminium oxide forms aluminium atoms and oxygen atoms.
Based on the electronic configuration the elements are classified as metals, non metals and metalloids.
<u>Explanation:</u>
Periodic table consists of three major parts.
The left side consists of metals and the right side consists of non-metals and here Hydrogen element is the exception and in between those two regions we have metalloids, which has the dual character of both metals and non metals.
These elements can be grouped by means of its chemical properties and also due to its outermost electronic configuration.
If the valence shell electrons are same they are categorized under same group.
Answer:
The relationship is the "<em>variation</em><em> </em><em>of</em><em> </em><em>vapour</em><em> </em><em>pressure</em><em> </em><em>with</em><em> </em><em>temperature</em><em>"</em><em> </em>or <em>"</em><em> </em><em>the</em><em> </em><em>effect</em><em> </em><em>of</em><em> </em><em>vapour</em><em> </em><em>pressure</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>melting</em><em> </em><em>and</em><em> </em><em>boiling</em><em> </em><em>points</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>phase</em><em>"</em>