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MatroZZZ [7]
4 years ago
6

Imagine you had a bar of gold and decided to cut in half. You repeated this process until eventually you could no longer cut the

gold in half without splitting a single atom of gold. This would prove that gold is a(n)
a. mixture.
b. element.
c. compound.
d. mixture or compound.
Physics
2 answers:
Paha777 [63]4 years ago
8 0
So we observed that no matter how small we make it by cutting, we get only gold and the smallest particle is also gold. So gold is an element
nydimaria [60]4 years ago
3 0

This would prove that gold is an <em>element</em>.  No matter how far down you
examine it, you never find any particles of anything except gold.

An example of a different case is salt. 
-- Imagine you had a block of salt and decided to cut it in half.
-- If you repeated this process, then eventually, at some point, you'd have
a tiny particle of salt in front of you, just like before.  BUT ...
-- Just as you were getting ready to cut this one in half, you'd notice that this
particle of salt is different.  It's one atom of sodium stuck to one atom of chlorine,
and if you cut it in half, you would not have ANY salt.   <span />

This would prove that salt is a <em><u>compound</u></em>, made of atoms of two or more elements.

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The rate at which a candle burns in millimeters per minute is:
anzhelika [568]
since both components, length and time, are measurable 
<span>since Rate = length ÷ time </span>
<span>∴ rate is also measurable and ∴ quantitative.

</span>
3 0
3 years ago
A rock is thrown vertically upward with a speed of 18.0 m/s from the roof of a building that is 50.0 m above the ground. Assume
Andreyy89

Answer:

(a) 5.7 s

(b) 39 m/s

Explanation:

(a) u = 18 m/s

At the maximum height, the final velocity of ball is zero. lte teh time taken by the ball to go from 50 m height to maximum height is t.

use first equation of motion.

v = u + g t

0 = 18 - 10 x t

t = 1.8 s

Let the maximum height attained by the ball when it thrown from 50 m height is h'.

Use third equation of motion

v^2 = u^2 + 2 g h'

0 = 18^2 - 2 x 10 x h'

h' = 16.2 m

Total height from the ground H = h + h' = 50 + 16.2 = 76.2 m

Let t' be the time taken by the ball to hit the ground as it falls from maximum height.

use third equation of motion

H = ut + 1/2 x g t'^2

76.2 = 0 + 1/2 x 10 x t'^2

t' = 3.9 s

Total time taken by the ball to hit the ground = T = t + t' = 1.8 + 3.9 = 5.7 s

(b) Let v be the velocity with which the ball strikes the ground.

v^2 = u^2 + 2 g H

v^2 = 0 + 2 x 10 x 76.2

v = 39 m/s

4 0
4 years ago
What is the answer to 17 ‐ 12× ‐ 18 ‐ 5×
Nastasia [14]
The answer is -17x-1. You have to combine like terms.
7 0
4 years ago
What are the four main reasons as to why, despite having an abundance of minerals and natural resources, Pakistan has been unabl
Andre45 [30]

Answer:

GDP growth rate is low

Political instability

Lack of technical skills due to low literacy rate

Pressure from neighboring countries

Explanation:

Gross Domestic Product growth rate of Pakistan is much lower than many developed countries. The GDP growth rate for Pakistan is nearly 5% which is not even stable and it variate from plans. Due to which Pakistan is unable to use its available resources to the fullest. Also one of major issue is political instability in the country. After the loss of great leader Quaid e Azam Pakistan has not faced any loyal leader till date.

Noise pollution, health issues, lack of provision of basic necessities to many are few other factors which give rise to poor law and order situation in the country. Lack of availability of heavy machinery and poor infrastructure has contributed to the country decline. There is abundance of natural resources in the country but due to these issues the country is unable to deal with the challenges.

The pressures from neighboring countries have made the situation even worst. The heavy loan burden is restricting the country from development. The covenants imposed by the lenders have limited the country's ability to use its natural resources and become stable.

5 0
3 years ago
What kind of image is formed by an object that is placed beyond the center of curvature on the principal axis of a concave mirro
Delicious77 [7]
As it is outside the focal point it must be real.Real images must be inverted.
As it is beyond the centre of curvature it is also beyond 2F which means that the image is inside the centre of curvature ( between F and 2F from the mirror ) As the image is closer to the mirror than the object it must be diminished in size.

Hope this helps you :)
8 0
3 years ago
Read 2 more answers
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