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Debora [2.8K]
3 years ago
6

A common neutralization reaction, that is used in titrations, involves sodium hydroxide, NaOH, reacting with nitric acid, HNO3.

What are the products of this reaction?
Chemistry
2 answers:
NeX [460]3 years ago
5 0

<u>Answer:</u> The products of the reaction are NaNO_3\text{ and }H_2O

<u>Explanation:</u>

Neutralization reaction is defined as the reaction when an acid reacts with a base to produce a salt and water molecule.

The chemical equation for the reaction of sodium hydroxide and nitric acid follows:

NaOH+HNO_3\rightarrow NaNO_3+H_2O

By Stoichiometry of the reaction:

1 mole of sodium hydroxide reacts with 1 mole of nitric acid to produce 1 mole of sodium nitrate and 1 mole of water.

Hence, the products of the reaction are NaNO_3\text{ and }H_2O

sertanlavr [38]3 years ago
4 0
The  common  neutralization  reaction  that  involve  NaOH  reacting   with  HNO3  produces

NaNO3     and  H2O

The  equation  for  reaction  is      as folows
NaOH  + HNO3  =  NaNO3  +  H2O 
that  is  1  mole  of  NaOH  reacted  with  1  mole  of  HNO3  to  form  1  mole  of  NaNO3  and  1  mole  of  H2O
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I think C. Hope this Helps!

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Using only the 1h nmr spectrum of the crude nitration product, determine if the product is mostly ortho-, meta-, or para- substi
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<span>The nitartion of methyl benzoate is expected to proceed as given in the equation below:

</span>

In methyl benzoate there are 3 types of 1 H proton. The two ortho to the C=O group is a doublet at 8 ppm the 2 metal to the C=O is a multiple at 7.5 ppm and one para to the C=O is a multiplet at 7.5 ppm.

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3 years ago
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Explanation:

To answer this question, we'll need to use the Ideal Gas Law:

p

V

=

n

R

T

,

where

p

is pressure,

V

is volume,

n

is the number of moles

R

is the gas constant, and

T

is temperature in Kelvin.

The question already gives us the values for

p

and

T

, because helium is at STP. This means that temperature is

273.15 K

and pressure is

1 atm

.

We also already know the gas constant. In our case, we'll use the value of

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We can find the value for

n

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n

=

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=

mass of sample

molar mass

=

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4.00 g/mol

=

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V

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p

V

=

n

R

T

V

=

n

R

T

p

=

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×

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×

273.15 K

1 atm

= 33.6 L

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