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Debora [2.8K]
3 years ago
6

A common neutralization reaction, that is used in titrations, involves sodium hydroxide, NaOH, reacting with nitric acid, HNO3.

What are the products of this reaction?
Chemistry
2 answers:
NeX [460]3 years ago
5 0

<u>Answer:</u> The products of the reaction are NaNO_3\text{ and }H_2O

<u>Explanation:</u>

Neutralization reaction is defined as the reaction when an acid reacts with a base to produce a salt and water molecule.

The chemical equation for the reaction of sodium hydroxide and nitric acid follows:

NaOH+HNO_3\rightarrow NaNO_3+H_2O

By Stoichiometry of the reaction:

1 mole of sodium hydroxide reacts with 1 mole of nitric acid to produce 1 mole of sodium nitrate and 1 mole of water.

Hence, the products of the reaction are NaNO_3\text{ and }H_2O

sertanlavr [38]3 years ago
4 0
The  common  neutralization  reaction  that  involve  NaOH  reacting   with  HNO3  produces

NaNO3     and  H2O

The  equation  for  reaction  is      as folows
NaOH  + HNO3  =  NaNO3  +  H2O 
that  is  1  mole  of  NaOH  reacted  with  1  mole  of  HNO3  to  form  1  mole  of  NaNO3  and  1  mole  of  H2O
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What is the enthalpy of reaction?
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Answer:

Enthalpy is the amount of heat released or absorb. The total enthalpy can be found by subtracting the products' enthalpy by the reactants' enthalpy

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Explain, in terms of particles, what happens when methane boils and why
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Answer:Butane > ethane > methane, because between bigger molecules there are stronger van der Waals forces and also higher molar mass means they need to be given more energy to have enough kinetic energy to move quickly, freely in gas.

There are multiple butene isomers (Butene) and some (2-Butenes - cis and trans) actually have higher boiling point than n-Butane (there is also Isobutane, of course, with quite much lower boiling point than all of them) and some (1-Butene, Isobutylene) have lower, so this isn't really a fair or simple question. But on simplest level, it can again be said that 1-butene has lower boiling point because it has very similar shape but slightly lower molar mass (2H less) than n-butane.

Explanation:

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2 years ago
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When magnesium reacts with hydrochloric acid, hydrogen gas is formed: 2HCl + Mg → H2 + MgCl2. What is the volume of hydrogen pro
Maksim231197 [3]

Answer:- C. 16.4 L

Solution:- The given balanced equation is:

2HCl+Mg\rightarrow H_2+MgCl_2

From this equation, there is 2:1 mol ratio between HCl and hydrogen gas. First of all we calculate the moles of hydrogen gas from given grams of HCl using stoichiometry and then the volume of hydrogen gas could be calculated using ideal gas law equation, PV = nRT.

Molar mass of HCl = 1.008 + 35.45 = 36.458 gram per mol

The calculations are shown below:

49.0gHCl(\frac{1molHCl}{36.458gHCl})(\frac{1molH_2}{2molHCl})

= 0.672molH_2

Now we will use ideal gas equation to calculate the volume.

n = 0.672 mol

T = 25 + 273 = 298 K

P = 101.3 kPa = 1 atm

R = 0.0821\frac{atm.L}{mol.K}

PV = nRT

1(V) = (0.672)(0.0821)(298)

V = 16.4 L

From calculations, 16.4 L of hydrogen gas are formed and so the correct choice is C.

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Lapatulllka [165]
I think the answer is B
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2 years ago
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