Answer:
Hello - this is Mrs. Gussman, your chemistry teacher. I wrote this exam question and posting it online is a violation of the academic integrity policy. Remove this post immediately.
Explanation:
Answer:
A weak acid
Explanation:
Im not sure if its right. But lets see someone else do it.
Answer:
![[A_t]=54.5\ g](https://tex.z-dn.net/?f=%5BA_t%5D%3D54.5%5C%20g)
Explanation:
Given that:
Half life = 14.0 days
Where, k is rate constant
So,
The rate constant, k = 0.04951 days⁻¹
Initial concentration [A₀] = 60.0 g
Time = 46.7 hrs
Considering, 1 hr = 0.041667 days
So, time = 1.9458 days
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
So,
![[A_t]=60.0\times e^{-0.04951\times 1.9458}\ g](https://tex.z-dn.net/?f=%5BA_t%5D%3D60.0%5Ctimes%20e%5E%7B-0.04951%5Ctimes%201.9458%7D%5C%20g)
Answer:
We use the following formula as given below Use the formula below to find the lone pair on the oxygen atom of the SO3 molecule. L.P (O) = V.E (O) – N.A (S-O) Lone pair on the terminal oxygen atom in SO3 = L.P (O)
Explanation:
