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o-na [289]
3 years ago
11

In the reaction K2CrO4(aq) + PbCl2(aq) → 2KCl(aq) + PbCrO4(s), how many grams of PbCrO4 will precipitate out from the reaction b

etween 500.0 milliliters of 3.0 M K2CrO4 in an excess of PbCl2?
1.5 grams

3.0 grams

480 grams

150 grams
Chemistry
1 answer:
Elodia [21]3 years ago
7 0
The balanced chemical reaction is:

<span>K2CrO4(aq) + PbCl2(aq) → 2KCl(aq) + PbCrO4(s)

We are given the amount of the reactants to be used for the reaction. These amounts will be the starting point of our calculations. </span>

<span>
3.0 M K2CrO4 (.500 L) = 1.5 mol K2CrO4

</span>1.5 mol K2CrO4 (1 mol PbCrO4 / 1 <span>mol K2CrO4</span>) ( 323.2 g/mol)=484.8 grams PbCrO4


Therefore, the best answer from the choices is 480 grams.

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0.17 moles

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In the elements of the periodic table, the atomic mass = molar mass. <u>Ex:</u> Atomic mass of Carbon is 12.01 amu which means molar mass of Carbon is also 12.01g/mol.

In order to find the # of moles in a 12 g sample of NiC-12, we will need to multiply the number of each atom by its molar mass and then add the masses of both Nickel and C-12 found in the periodic table:

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Since there's just one atom of both Carbon and Nickel, we just add up the masses to find the molar mass of the whole compound of NiC-12.

  • 58.69 g/mol of Nickel + 12.01 g/mol of Carbon = 70.7 g/mol of NiC-12

There's 12g of NiC-12, which is less than the molar mass of NiC-12, so the number of moles should be less than 1. In order to find the # of moles in NiC-12, we need to do some dimensional analysis:

  • 12g NiC-12 (1 mol of NiC-12/70.7g NiC-12) = 0.17 mol of NiC-12
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