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Aleksandr [31]
3 years ago
13

How many grams of oxygen are required to react with 12.0 grams of octane in the combustion of octane in gasoline?

Chemistry
1 answer:
Svetach [21]3 years ago
6 0
2 C8H18(g) + 25 O2(g) → 16 CO2(g) + 18 H2O(g) 

<span>(10.0 g C8H18) / (114.2285 g C8H18/mol) x (25 mol O2 / 2 mol C8H18) x (31.99886 g O2/mol) = 35.0 g O2
please return the favor and answer question in my profile thanks 
</span>
You might be interested in
If a gas at 25.0 °C occupies 3.60 liters at a pressure of 1.00 atm, what will be its volume at a pressure of 2.50 atm?
Greeley [361]

Answer:

1.44 L

Explanation:

Since 25 is constant it is no use. Now, rearrange the gas formula. You should get...

P1V1/T2=P2V2T1

Next, rearrange to fit the problem. You should get...

V2=P1V1/P2

Fill in our values and solve. You should get 1.44 L

We can check this by knowing that P and V at constant T have an inverse relationship. Hence, this is correct.

- Hope that helps! Please let me know if you need further explanation.

8 0
3 years ago
The following situations are presented to a medical examiner. In which situation is the medical examiner most likely to gather m
kolezko [41]
B) 25-year-old male recovered from rapids after his empty kayak is sited by friends 
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8 0
3 years ago
Why must the ph ammonia buffer solution be stored and dispensed in the fume exhaust hood?
Vadim26 [7]

On the other hand ammonia is a very dangerous chemical which has a pungent smell and effect the eyes of the user. Thus it kept always in the fume exhaust hood for storing and dispensing function.  

The  pH of ammonia buffer contains ammonium hydroxide (NH₄OH) and a salt of ammonia with a  strong acid like (HCl) which produces, ammonium chloride (NH₄Cl) mixture. The evaporation rate of ammonia is so high at room temperature thus on opening of the buffer solution the ammonia get evaporated very fast and the concentration of ammonia decreases which affect the pH of the buffer solution.

Thus the reason to put ammonia buffer in fume hood is explained.


7 0
3 years ago
A balloon has a volume of 6.2 liters at 23.2 C. The balloon is then heated to a temperature of 144.0 C. What is the volume of th
Marina CMI [18]

Answer:

8.7 L

Explanation:

T2(V1/T1) = V2

417.15 K(6.2 L/296.45 K) = 8.7 L

Remember to almost always change celcius to kelvin. Also, this is part of Charle's Law (temp and volume are proportional, so if temp increaces so must the volume or vice versa). Lastly, Charle's Law has the formula of V1/T1 = V2/T2. I just rearranged it to go along with your problem. Hence, the T2(V1/T1) = V2

4 0
4 years ago
Give the spectator ions for the reaction that occurs when aqueous solutions of H 2SO 4 and KOH are mixed.
Sever21 [200]

Answer:

The spectator ions is: K^+   and  SO^{2-}_4

Explanation:

The equation of reaction between  H₂ SO₄ and KOH is:

H_2SO_{4(aq)} + 2KOH _{aq} \to K_2SO_{4(aq)} +2H_2O _{(l)}

Rewriting this equation as ionic;

[2H^{+} + SO^{2-}_4 + 2K^+ +2OH^- \to 2K^+  SO_4^{2-} + 2H_2O ]

Spectators ions are ions present on both sides of the ionic equation by the same quantity but do not take part in the net reaction.

5 0
3 years ago
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