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Aleksandr [31]
3 years ago
13

How many grams of oxygen are required to react with 12.0 grams of octane in the combustion of octane in gasoline?

Chemistry
1 answer:
Svetach [21]3 years ago
6 0
2 C8H18(g) + 25 O2(g) → 16 CO2(g) + 18 H2O(g) 

<span>(10.0 g C8H18) / (114.2285 g C8H18/mol) x (25 mol O2 / 2 mol C8H18) x (31.99886 g O2/mol) = 35.0 g O2
please return the favor and answer question in my profile thanks 
</span>
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Explanation:

Solving this question would be easier by assigning variables.

so, let x = amount of 67% needed solution

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we also know that the pure herbicide in the 67% solution plus the herbicide I'm the 46% solution must be equal to the amount of pure herbicide in the final solution. Thus mathematically, we have

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