Answer:
The correct answer is "430 kJ/kg". A further explanation is given below.
Explanation:
The given values are:
T₁ = 400 k
T₂ = 800 k
The average temperature will be:
= 
= 
= 
From table,
At 600 k the 
will be = 1.075
Now,
⇒ The specific enthalpy = 
⇒ 
⇒ 
0.0005411
0.00054 is the real answer
you use the one with the least significant figures as the reference of how many to use.
101 three sig figs
001 one sig figs as well as 0.001
9.000 four sig figs
Na3 = 23*3 = 69
P = 31
O4 = 16*4 =64
69+ 31+ 64 = 164g/mol
0.75mol = 0.75 * 164 = 123 g
Answer:
The initial temperature is 499 K
Explanation:
Step 1: Data given
initial volume = 12 cm3 = 12 mL
Final volume = 7 cm3 = 7mL
The final temperature = 18 °C = 291 K
Step 2: Calculate the initial temperature
V1/T1 = V2/T2
⇒with V1 = the initial volume = 0.012 L
⇒with T1 = the initial volume = ?
⇒with V2 = the final volume 0.007 L
⇒with T2 = The final temperature = 291 K
0.012 / T1 = 0.007 / 291
0.012/T1 = 2.4055*10^-5
T1 = 0.012/2.4055*10^-5
T1 = 499 K
The initial temperature is 499 K
Answer:
Calcium carbonate
Explanation:
Ionic compounds that tend to have one or more polyatomic ions are the ones that tend to exhibit both ionic and covalent bonding. The only one that meets this is calcium carbonate.
