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3 years ago

How many grams of oxygen are required to react with 12.0 grams of octane in the combustion of octane in gasoline?

1 answer:

6 0

2 C8H18(g) + 25 O2(g) → 16 CO2(g) + 18 H2O(g)

<span>(10.0 g C8H18) / (114.2285 g C8H18/mol) x (25 mol O2 / 2 mol C8H18) x (31.99886 g O2/mol) = 35.0 g O2
please return the favor and answer question in my profile thanks
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Select the atom that will attract the electron pair (:) more strongly (the atom with the greater electronegativity)

masha68 [24]

24. F:H :) because Fluorine is the most electronegative

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2 years ago

Draw the partial (valence-level) orbital diagram, and write the symbol, group number, and period number of the element:

Lapatulllka [165]

Answer:

a) The element is Manganese (Mn)

b) The element is Zirconium (Zr)

Explanation:

The step by step analysis and explanation is as shown in the attachment

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2 years ago

While you were "sweating" your chemistry test, water vapor evaporates from your body, absorbing 50,000 J of energy. (assume no

TiliK225 [7]

Answer:

$\boxed {\boxed {\sf B. \ 22 \ grams}}$

Explanation:

We need to use the formula for heat of vaporization.

$Q=H_{vap}*m$

Identify the variables.

The heat absorbed by the evaporating water is the <u>latent heat of vaporization. </u>For water, that is 2260 Joules per gram.

Q is the energy, in this problem, 50,000 Joules.

m is the mass, which is unknown.

$H_{vap}=2260 \ J/g\\Q=50,000 \ J \\$

Substitute the values into the formula.

$50,000 \ J=2260 \ J/g*m$

We want to find the mass. We must isolate the variable, m.

m is being multiplied by 2260 J/g. The inverse operation of multiplication is division. Divide both sides by 2260 J/g.

$\frac{50,000 \ J}{2260 \ J/g} =\frac{2260 \ J/g*m}{2260 \ J/g}$

$\frac{50,000 \ J}{2260 \ J/g} =m$

Divide. Note that the Joules (J) will cancel each other out.

$\frac{50,000 \ }{2260 \ g} =m$

$22.1238938 \ g =m$

Round to the nearest whole number. The 1 in the tenth place tells us to leave the number as is.

$22 \ g \approx m$

The mass is about 22 grams, so choice B is correct.

3 0

2 years ago

sound travels slower in colder air than it does in warmer air why does the speed of sound depend on air temperature

Marta_Voda [28]

Answer:

Explanation:

The speed of sound in the air mainly depends on temperature. At high altitudes, where it is much colder, sound travels slower. The higher the temperature, the faster the air molecules are moving to begin with, and the quicker they bump into each other as a sound wave passes through.

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3 years ago

Read 2 more answers

What are the primary colors?

guapka [62]

The primary colors are blue, red, and yellow.

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2 years ago