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Aleksandr [31]
3 years ago
13

How many grams of oxygen are required to react with 12.0 grams of octane in the combustion of octane in gasoline?

Chemistry
1 answer:
Svetach [21]3 years ago
6 0
2 C8H18(g) + 25 O2(g) → 16 CO2(g) + 18 H2O(g) 

<span>(10.0 g C8H18) / (114.2285 g C8H18/mol) x (25 mol O2 / 2 mol C8H18) x (31.99886 g O2/mol) = 35.0 g O2
please return the favor and answer question in my profile thanks 
</span>
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What is the diffrence between acidic and basic solutions in working with redox reactions?
Leno4ka [110]
In acidic solutions you have H+ but in basic solutions you have OH-.
You need know that for to balance the reaction.
3 0
3 years ago
An adult mosquitoes lifespan is about 16 days how many minutes is that
AVprozaik [17]
The answer is 23, 040 minutes. To solve this you can start by changing days in to hours. We know that there are 24 hours in a day. To find how many hours are in 16 days you multiply 24 by 16 which is 384. Next you must find out how many minutes are in 384 hours. we know there are 60 minutes per hour. To find how many minutes are in 384 hours, you multiply 384 by 60. To this you get 23, 040 which is your answer.
3 0
3 years ago
Complete the following equations : H3PO4 = 3H+ --------------- CaSO4 = Ca 2+ ---------------- (2) b) Write the formulae of the s
jeka94

Answer:

H₃PO₄ → 3H⁺ + PO₄³⁻

CaSO₄ → Ca²⁺ + SO₄²⁻

b. CaCl₂

Explanation:

When H₃PO₄ is dissolved in water, there are produced the H⁺ and PO₄³⁻ ions. The equation is:

H₃PO₄ → 3H⁺ + PO₄³⁻

In the same way, CaSO₄ is dissolved in:

CaSO₄ → Ca²⁺ + SO₄²⁻

b. Now, in a reaction of an acid (HCl) and a base (Ca(OH)₂), water, H₂O and a salt are produced:

2 HCl + Ca(OH)₂ → 2H₂O + Salt

The ions that are not present in the reaction are Cl⁻ and Ca²⁺, the salt is CaCl₂ and the balanced reaction is:

2 HCl + Ca(OH)₂ → 2H₂O + CaCl₂

5 0
2 years ago
Separate this redox reaction into its component half-reactions. 3o2 4co
swat32
The equation is:
3 O₂ + 4 Co → 2 Co₂O₃
Oxidation half reaction:
Co → Co³⁺ + 3 e
Reduction half reaction:
O₂ + 4 e → 2 O²⁻
To balance the equation number of electrons lost must be equal to number or electrons gained so we must multiply oxidation half time 4 and reduction half times 3
3 0
3 years ago
Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi
bija089 [108]

<u>Answer:</u> The value of K_c for the net reaction is \frac{K_b}{K_w}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b

<u>Equation 2:</u>  H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}

The net equation follows:

B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=K_1\times K_2

We are given:  

K_1=K_b

K_2=\frac{1}{K_w}

Putting values in above equation, we get:

K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}

Hence, the value of K_c for the net reaction is \frac{K_b}{K_w}

7 0
3 years ago
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